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Answer:
It would be number 3. 1/7,3/7,4/7,6/7
Step-by-step explanation:
For fractions if the denominator is the same you go to the numerator (the top number) to compare. The bigger the numerator is (like 6) the higher it should go on your list.
Let x,y,z be those numbers.
x+y+z = 12
Since x,y,z are consecutive: y=x+1, and z = x+2
Let's replace y and z by their new values:
x+x+1+x+2=12
3x+3=12
You subtract 3 from each side to get variables on a side, and numbers on the other:
3x=9
You divide both sides by 3:
x=3
y=x+1 = 3+1 = 4
z=x+2 = 3+2 = 5
So the numbers are 3; 4 and 5.
You can re-check your answers (very important):
3+4+5 = 12
3;4;5 are consecutive numbers.
The answer has been approved.
Hope this Helps! :)
Answer:
Trying to solve this leads to an absurdity, so No Solution.
Step-by-step explanation:
5x+12=5x−7
Lets attempt to solve:
Subtract 5x from both sides
5x - 5x + 12 = 5x - 5x - 7
0 + 12 = 0 - 7
12 = -7
This is absurd so there is no solution.