What is the product? StartFraction 2 a minus 7 Over a EndFraction times StartFraction 3 a squared Over 2 a squared minus 11 a +

Question

3 years ago

4

14 EndFraction

2 answers:

Ne4ueva [31] · Answer 1 · 2022-05-03T11:35:26+03:00

6 0

Answer:

The product is $\frac{3a}{a-2}$ .

Step-by-step explanation:

The expression is:

$\frac{2a-7}{a}\times \frac{3a^{2}}{2a^{2}-11a+14}$

Simplify as follows:

$\frac{2a-7}{a}\times \frac{3a^{2}}{2a^{2}-11a+14}=(2a-7)\times \frac{3a}{2a^{2}-7a-4a+14}$

$=(2a-7)\times \frac{3a}{a(2a-7)-2(2a-7)}\\\\=(2a-7)\times \frac{3a}{(a-2)(2a-7)}\\\\=\frac{3a}{a-2}$

Thus, the product is $\frac{3a}{a-2}$ .

antoniya [11.8K] · Answer 2 · 2022-05-03T13:40:48+03:00

6 0

Answer:

the answer to this question is B.

Step-by-step explanation: