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netineya [11]
4 years ago
5

Find the number of positive three-digit even integers whose digits are among 9, 8, 7, 5, 3, and 1.

Mathematics
2 answers:
Volgvan4 years ago
8 0
<h2>Answer:</h2>

The number of positive three-digit even integers whose digits are among 9, 8, 7, 5, 3, and 1 are:

                               36

<h2>Step-by-step explanation:</h2>

We are asked to find the number of positive three-digit even integers whose digits are among 9, 8, 7, 5, 3, and 1.

We know that a number is even if the last digit of the number is divisible by 2 i.e. even.

Hence, the only digits among the given digits which is even is: 8

Now, at the first place any of the 6 digits could come up.

( Since, the digits could be repeated)

Also, at the second palace any of the 6 digits could come up.

Hence, the total number of such numbers possible are:

                 6×6×1=36

agasfer [191]4 years ago
6 0

Answer:

8

Step-by-step explanation:

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Step-by-step explanation:

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Complete the square to solve the equation below.<br> X^2 +x=11/4
victus00 [196]

Answer:

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Step-by-step explanation:

* Lets revise how to make the completing square

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