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alex41 [277]
3 years ago
10

What Word feature is seen below?

Computers and Technology
1 answer:
nika2105 [10]3 years ago
3 0

hi there


!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!





<em><u>it c the ribbon tab. just want  to help .</u></em>





!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!


hope this helps. if you want please mark brainlyist. enjoy





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1st row has 3 possible answers software program, web page, and web browser
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1st row: software program

2nd row: a user's computer

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Write an application that inputs three numbers (integer) from a user. (10 pts) UPLOAD Numbers.java a. display user inputs b. det
SCORPION-xisa [38]

Answer:

The program to this question as follows:

Program:

import java.util.*; //import package for user input

public class Number //defining class Number

{

public static void main(String[] ak)throws Exception //defining main method

{

int a1,b1,c1; //defining integer variable

int p_Count=0,n_Count=0,n_Zero=0,even_Count=0,odd_Count=0;

Scanner obx=new Scanner(System.in); //creating Scanner class object

System.out.println("Input all three numbers: "); //print message

//input from user

a1=obx.nextInt(); //input value

b1=obx.nextInt(); //input value

c1=obx.nextInt(); //input value

//check condition for a1 variable value

if(a1>0) //positive number

p_Count++;

else if(a1==0) //value equal to 0

n_Zero++;

else //value not equal to 0

n_Count++;

if(a1%2==0)//check even number

even_Count++;

else //for odd number

odd_Count++;

//check condition for b1 variable value

if(b1>0) //positive number

p_Count++;

else if(b1==0) //value equal to 0

n_Zero++;

else //value not equal to 0

n_Count++;

if(b1%2==0) //check even number

even_Count++;

else //for odd number

odd_Count++;

//check condition for c1 variable value

if(c1>0) //positive number

p_Count++;

else if(c1==0) //value equal to 0

n_Zero++;

else //value not equal to 0

n_Count++;

if(c1%2==0) //check even number

even_Count++;

else //for odd number

odd_Count++;

//print values.

System.out.println("positive number: "+p_Count);//message

System.out.println("negative number: "+n_Count); //message

System.out.println("zero number: "+n_Zero); //message

System.out.println("even number: "+even_Count); //message

System.out.println("odd number: "+odd_Count); //message

}

}

Output:

Input all three numbers:

11

22

33

positive number: 3

negative number: 0

zero number: 0

even number: 1

odd number: 2

Explanation:

In the above java program code a class is defined in this class three integer variable "a1,b1, and c1" is defined which is used to take input value from the user end, and other integer variable "p_Count=0, n_Count=0, n_Zero=0, even_Count=0, and odd_Count=0" is defined that calculates 'positive, negative, zero, even, and odd' number.

  • In the next step, the conditional statement is used, in if block a1 variable, b1 variable, c1 variable calculates it checks value is greater then 0, it will increment the value of positive number value by 1.
  • else if it will value is equal to 0. if this condition is true it will negative number value by 1
  • else it will increment zero number values by 1.
  • In this code, another if block is used, that checks even number condition if the value matches it will increment the value of even number by 1, and at the last print, method is used that print all variable values.
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the first row of the table is know as the table header.

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