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luda_lava [24]
3 years ago
5

Please help i dont understand it and the end of grading cycle is today!

Mathematics
1 answer:
GarryVolchara [31]3 years ago
6 0

Answer:

( 4.5 , 5.25 )

Step-by-step explanation:

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I need help with this practice problem solving This is trigonometry from my ACT prep guide
Novay_Z [31]

Take into account, that in general, a cosine function of amplitude A, period T and vertical translation b, can be written as follow:

f(x)=A\cos (\frac{2\pi}{T}x)+b

In the given case, you have:

A = 4

T = 3π/4

b = -3

By replacing you obtain:

\begin{gathered} f(x)=4\cos (\frac{2\pi}{\frac{3\pi}{4}}x)-3 \\ f(x)=4\cos (\frac{8}{3}x)-3 \end{gathered}

Hence, the answer is:

f(x) = 4cos(8/3 x) - 3

6 0
1 year ago
The standard normal curve shown below is a probability density curve for a
Step2247 [10]

Answer:

0.6825

Explanation:

I'm not fully sure about how to do this, but I believe it might have to do with

the approx. amount of shade, but please take this explanation with a grain of salt as I'm not 100% certain. I am certain about the answer however.

8 0
3 years ago
a box cost $2.48, but it is on sale for $1.49. How much do you save on one box when bought on sale? Now how much would you save
Thepotemich [5.8K]

Answer:

1. $0.99

2. $1.98

Step-by-step explanation:

1. From the question we have

Cost of box = $2.48

Selling price = $1.49

That is the box is discounted from $2.48 to $1.49

Therefore, amount saved = $2.48 - $1.49 = $0.99

2. The amount saved from buying a second box is hence;

2 × $0.99 = $1.98

Hence, as the number of boxes bought increases, the amount saved increases

5 0
3 years ago
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Please don’t only answer this explain how to figure it out so I have it for future reference
Deffense [45]
The polygon is built of 7 triangles (picture).

P=7\cdot\dfrac{1}{2}ah\\
a=28.9 \text{ m}\\
h=30 \text{ m}\\\\
P=7\cdot\dfrac{1}{2}\cdot28.9\cdot30\\
P=3034.5 \text { m}^2 \Rightarrow C

5 0
3 years ago
If f(x)=log2(x+4), what is f^-1(3)?
zalisa [80]
f\left( x \right) =\log _{ 2 }{ \left( x+4 \right)  } \\ \\ \log _{ 2 }{ \left( x+4 \right)  } =y\\ \\ { 2 }^{ y }=x+4

\\ \\ x={ 2 }^{ y }-4\\ \\ \therefore \quad { f }^{ -1 }\left( x \right) ={ 2 }^{ x }-4\\ \\ \therefore \quad { f }^{ -1 }\left( 3 \right) ={ 2 }^{ 3 }-4=4
3 0
4 years ago
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