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2 years ago

What is the vertical asymptote for this function? y=1/x-2

Mathematics

1 answer:

nataly862011 [7]2 years ago

8 0

Answer: x = 0

Step-by-step explanation: so x = 0 is the equation of the vertical asymptote, and 0 must be left out of the domain: (−∞,0)U(0,∞) in interval notation.

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3 years ago

Need help with this question I got it wrong

Zinaida [17]

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2 years ago

Read 2 more answers

The U.S. Department of Transportation provides the number of miles that residents of the75 largest metropolitan areas travel per

Leya [2.2K]

Answer:

a. The point estimate of the difference between the mean number of miles that Buffalo residents travel per day and the mean number of miles that Boston residentstravel per day is 88

b. The 95% confidence interval for the difference between the two population means is (0.58171,7.21829)

Step-by-step explanation:

a. According to the given data we have the following:

Buffalo residents mean=22.5

Standard deviation=8.4

n=50

Boston residents mean=18.6

Standard deviation=7.4

n=40

Hence, the point estimate is the difference of the means=22.5-18.6=3.9

The standard error=√((s1∧2/n1)+((s2∧2/n2))=√((8.4∧2/50)+(7.4∧2/40))=1.67

Therefore, the difference of miles=n1+n2-2=50+40-2=88

The point estimate of the difference between the mean number of miles that Buffalo residents travel per day and the mean number of miles that Boston residentstravel per day is 88.

b. The critical value of t at 95% confidence level and DoF=88 is 1.987

The interval:(x1-x2)+ (critical value* std error)

=3.9-(1.987*1.67),3.9+(1.987*1.67)

Difference between mean=(0.58171,7.21829)

The 95% confidence interval for the difference between the two population means is (0.58171,7.21829)

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2 years ago

As an aid to the establishment of personnel requirements, the director of a hospital wishes to estimate the mean number of peopl

GenaCL600 [577]

Answer:

n = 66.564

Step-by-step explanation:

Because the population is unknown, we will apply the following formula to find the sample size:

$n= (\frac{zS}{E} )^{2}$

Where:

z = confidence level score.

S = standard deviation.

E = error range.

2. We will find each of these three data and replace them in the formula.

"z" theoretically is a value that measures how many standard deviations an element has to the mean. For each confidence level there is an associated z value. In the question, this level is 99%, which is equivalent to a z value of 2.58. To find this figure it is not necessary to follow any mathematical procedure, it is enough to make use of a z-score table, which shows the values for any confidence interval.

The standard deviation is already provided by the question, it is S = 100.

Finally, "E" is the acceptable limit of sampling error. In the example, we can find this data. Let us note that in the end it says that the director wishes to estimate the mean number of admissions to within 1 admission, this means that she is willing to tolerate a miscalculation of just 1 admission.

Once this data is identified, we replace in the formula:

$n=(\frac{(2.58)(100)}{1} )^{2}$