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defon
3 years ago
10

What is the vertical asymptote for this function? y=1/x-2

Mathematics
1 answer:
nataly862011 [7]3 years ago
8 0

Answer: x = 0

Step-by-step explanation: so x = 0 is the equation of the vertical asymptote, and 0 must be left out of the domain: (−∞,0)U(0,∞) in interval notation.

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Find two integers whose sum is -20 and product is 99
Brums [2.3K]

Answer:

Step-by-step explanation:

let the integers be x and y

x+y=-20

y=-20-x

xy=99

x(-20-x)=99

-20x-x²=99

x²+20x+99=0

x²+11x+9x+99=0

x(x+11)+9(x+11)=0

(x+11)(x+9)=0

x=-11,-9

when x=-11

-11+y=-20

y=-20=11=-9

when x=-9

-9+y=-20

y=-20+9=-11

so integers  are -11,-9

8 0
2 years ago
Read 2 more answers
A=1/2 bh (base/height)<br> =.5(12)4<br> a=24ft<br> how did i get the answer a=24?
vampirchik [111]
That’s what i got
step by step explanation
4 0
3 years ago
3x+3=2x+1 what is the value of x
allsm [11]

Answer:

Answer: 3x + 3 = 2x + 1

Answer: 3x + 3 = 2x + 1 <=>3x - 2x = 1 - 3

Answer: 3x + 3 = 2x + 1 <=>3x - 2x = 1 - 3 <=> x = -2

7 0
3 years ago
Find the square root of :<br> √50×8 = ___<br> Please show steps....
Sav [38]
Your answer would be 20.. the square root of 50 is 7.07106781187 x by 8
6 0
3 years ago
If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)
sweet-ann [11.9K]

Answer:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

Step-by-step explanation:

Given

tan\theta = 3

Required

Find

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)

Calculate tan(\theta + \pi) \ and\ tan(\theta+2\pi)

Using tan rule

tan(\theta + \pi)  = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}

So:

tan(\theta + \pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + \pi)  = \frac{tan\theta}{1 }

tan(\theta + \pi)  = \tan\theta

tan(\theta+2\pi)

tan(\theta + 2\pi)  = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}

tan(\theta + 2\pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + 2\pi)  = \tan\theta'

'So:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = tan\theta +tan\theta +tan\theta

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

4 0
3 years ago
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