Answer: 68
Step-by-step explanation:
Answer and Step-by-step explanation:
Given
ax + by = c
qx + ry = s
(a) the equation has no solutions if a/q = b/r ≠ c/s, when this happens, we say the system of equations has no solution. For example
x + y = 3
x + y = 5
Subtracting first equation from the second we have:
0 = 2 which is impossible.
(b) the equations have infinite solutions if a/q = b/r = c/s, for example
x + y = 2
x + y = 2
Subtracting the first equation from the second we have
0 = 0, since this is always true, then it has infinite solutions.
(c) the equations have unique solutions if a/q ≠ b/r, for example
x + y = 2
x – y = 1
Adding the first and second equation we have
2x = 3, we can get x from here and definitely y, so we have just one solution.
Answer:
f(5) = 136.71875
Step-by-step explanation:
f(5) if f(1)=3.5 and f(x+1)=5\2 f(x)
f(2) = (5/2)* f(1) = (5/2)* 3.5 = 8.75
f(3) = (5/3)*f(2) =(5/2) * 8.75
f(4) = (5/3)*f(3) =(5/2)*(5/2) * 8.75
f(5) = (5/3)*f(4) = (5/3)*(5/2)*(5/2) * 8.75
f(5) = (5/2)^4 * 3.5 = (625/16) * 3.5 = 136.71875
f(5) = 136.71875
Answer:
I am pretty sure its 30 students
