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melamori03 [73]
3 years ago
11

If a = 150 inches, b = 50 inches, and C = 120º find c. Round to the nearest tenth of an inch.

Mathematics
2 answers:
liraira [26]3 years ago
7 0

Answer:180.3

Step-by-step explanation:

a=150

b=50

C=120

c^2=a^2+b^2-2 x a x b x cosC

c^2=150^2+50^2-2x150x50xcos120

c^2=150x150+50x50-2x150x50xcos120

c^2=22500+2500-15000cos120

c^2=25000-15000x-0.5

c^2=25000+7500

c^2=32500

c=√(32500)

c=180.3

Musya8 [376]3 years ago
3 0

Answer:

180.3 inches

Step-by-step explanation:

Using cosine law:

c² = 150² + 50² - 1(150)(50)cos(120)

c² = 32500

c = 50sqrt(13)

c = 180.3 (nearest tenth)

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