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3 years ago

If a = 150 inches, b = 50 inches, and C = 120º find c. Round to the nearest tenth of an inch.

Mathematics

2 answers:

liraira [26]3 years ago

7 0

Answer:180.3

Step-by-step explanation:

a=150

b=50

C=120

c^2=a^2+b^2-2 x a x b x cosC

c^2=150^2+50^2-2x150x50xcos120

c^2=150x150+50x50-2x150x50xcos120

c^2=22500+2500-15000cos120

c^2=25000-15000x-0.5

c^2=25000+7500

c^2=32500

c=√(32500)

c=180.3

Musya8 [376]3 years ago

3 0

Answer:

180.3 inches

Step-by-step explanation:

Using cosine law:

c² = 150² + 50² - 1(150)(50)cos(120)

c² = 32500

c = 50sqrt(13)

c = 180.3 (nearest tenth)

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2 years ago

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riadik2000 [5.3K]

Answer:

We need an SRS of scores of at least 153.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

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Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large an SRS of scores must you choose?

This is at least n, in which n is found when $M = 20, \sigma = 150$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$20 = 1.645*\frac{150}{\sqrt{n}}$

$20\sqrt{n} = 1.645*150$

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Rounding to the next whole number, 153

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3 years ago