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3 years ago

10

Name the corresponding angle to <5

1 answer:

Nana76 [90]3 years ago

3 0

Answer:

Less than is the answer

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What is the product of (3x + 1)(3x – 4)?<br> Step by step.

kvasek [131]

Answer:

9x^2-9x-3

Step-by-step explanation:

3x*3x=9x^2

3x*-4=-12x

1*3x=3x

1*-4=-3

9x^2-12x+3x-3

9x^2-9x-3

7 0

3 years ago

Read 2 more answers

Multiple Choice: Please select the best answer.

PSYCHO15rus [73]

D. 171

-

Explanation:

4(2+5)^2 - 5^2

4 x 7^2 - 5^2

4 x 49 - 25

196 - 25

171

Answer: D. 171

7 0

3 years ago

Show locations on number line to plot the points 10/3 and 17/3

UNO [17]

Answer: See the figure attached.

Step-by-step explanation:

1. To solve this exercise and locate the numbers shown in the problem on the number line, you can convert them from fractions to decimal numbers by dividing the numerator by the denominator. Therefore, you obtain:

10/3=3.33

17/3=5.66

2. Now, you can draw a number line (like the one shown in the figure attached) and locate the numbers as you can see in the image.

6 0

3 years ago

6. If ABCD is a square and AD = 11. find each missing value.

MAVERICK [17]

Answer:

All sides will be 11 and all angles will be 90 degrees.

Step-by-step explanation:

As all sides of square are equal. And all angles are right angled.

Hope it helped!!

3 0

3 years ago

Sort the ratios listed at the right into bins so that equivalent ratios are grouped together:

cestrela7 [59]

Step $1$

<u>Find the irreducible fraction in each ratio</u>

<u>case 1)</u> $\frac{40}{64}$

Divide by $8$ boths numerator and denominator

$\frac{40}{64}=\frac{5}{8}$

<u>case 2)</u> $\frac{5}{75}$

Divide by $5$ boths numerator and denominator

$\frac{5}{75}=\frac{1}{15}$

<u>case 3)</u> $\frac{14}{35}$

Divide by $7$ boths numerator and denominator

$\frac{14}{35}=\frac{2}{5}$

<u>case 4)</u> $\frac{24}{64}$

Divide by $8$ boths numerator and denominator

$\frac{24}{64}=\frac{3}{8}$

<u>case 5)</u> $\frac{6}{15}$

Divide by $3$ boths numerator and denominator

$\frac{6}{15}=\frac{2}{5}$

<u>case 6)</u> $\frac{65}{104}$

Divide by $13$ boths numerator and denominator

$\frac{65}{104}=\frac{5}{8}$

<u>case 7)</u> $\frac{66}{176}$

Divide by $22$ boths numerator and denominator

$\frac{66}{176}=\frac{3}{8}$

<u>case 8)</u> $\frac{12}{30}$

Divide by $6$ boths numerator and denominator

$\frac{12}{30}=\frac{2}{5}$

<u>case 9)</u> $\frac{15}{225}$

Divide by $15$ boths numerator and denominator

$\frac{15}{225}=\frac{1}{15}$

<u>case 10)</u> $\frac{6}{16}$

Divide by $2$ boths numerator and denominator

$\frac{6}{16}=\frac{3}{8}$

<u>case 11)</u> $\frac{15}{24}$

Divide by $3$ boths numerator and denominator

$\frac{15}{24}=\frac{5}{8}$

<u>case 12)</u> $\frac{48}{128}$

Divide by $16$ boths numerator and denominator

$\frac{48}{128}=\frac{3}{8}$

Step $2$

<u>Sort the ratios into bins</u>

1<u>) First Bin</u>

<u> $Ratio=\frac{5}{8}$ </u>

$\frac{40}{64}$

$\frac{65}{104}$

$\frac{15}{24}$

<u>2) Second Bin </u>

<u> $Ratio=\frac{1}{15}$ </u>

$\frac{5}{75}$

$\frac{15}{225}$

<u>3) Third Bin</u>

$Ratio=\frac{2}{5}$

$\frac{14}{35}$

$\frac{6}{15}$

$\frac{12}{30}$

4<u>) Fourth Bin</u>

<u> $Ratio=\frac{3}{8}$ </u>

$\frac{24}{64}$

$\frac{66}{176}$

$\frac{6}{16}$

$\frac{48}{128}$

3 0

3 years ago

Read 2 more answers