All categories

3 years ago

Can a triangle be made with sides of length 7, 10 and 20?

Mathematics

1 answer:

salantis [7]3 years ago

3 0

Yes it can its called a scalene triangle

You might be interested in

Evaluate using integration by parts

PolarNik [594]

Rather than carrying out IBP several times, let's establish a more general result. Let

$I(n)=\displaystyle\int x^ne^x\,\mathrm dx$

One round of IBP, setting

$u=x^n\implies\mathrm du=nx^{n-1}\,\mathrm dx$

$\mathrm dv=e^x\,\mathrm dx\implies v=e^x$

gives

$\displaystyle I(n)=x^ne^x-n\int x^{n-1}e^x\,\mathrm dx$

$I(n)=x^ne^x-nI(n-1)$

This is called a power-reduction formula. We could try solving for $I(n)$ explicitly, but no need. $n=5$ is small enough to just expand $I(5)$ as much as we need to.

$I(5)=x^5e^x-5I(4)$

$I(5)=x^5e^x-5(x^4e^x-4I(3))=(x-5)x^4e^x+20I(3)$

$I(5)=(x-5)x^4e^x+20(x^3e^x-3I(2))=(x^2-5x+20)x^3e^x-60I(2)$

$I(5)=(x^2-5x+20)x^3e^x-60(x^2e^x-2I(1))=(x^3-5x^2+20x-60)x^2e^x+120I(1)$

$I(5)=(x^3-5x^2+20x-60)x^2e^x+120(xe^x-I(0))$

Finally,

$I(0)=\displaystyle\int e^x\,\mathrm dx=e^x+C$

so we end up with

$I(5)=(x^4-5x^3+20x^2-60x+120)xe^x-120e^x+C$

$I(5)=(x^5-5x^4+20x^3-60x^2+120x-120)e^x+C$

and the antiderivative is

$\displaystyle\int2x^5e^x\,\mathrm dx=(2x^5-10x^4+40x^3-120x^2+240x-240)e^x+C$

8 0

3 years ago

16-5(3t-4)=8(-2t+11) How to Solve

Hunter-Best [27]

16 - 5(3t - 4) = 8(-2t + 11) use distributive property: a(b + c) = ab + ac

16 - (5)(3t) - (5)(-4) = (8)(-2t) + (8)(11)

16 - 15t + 20 = -16t + 88

36 - 15t = -16t + 88 subtract 36 from both sides

-15t = -16t + 52 add 16t to both sides

t = 52

5 0

3 years ago

Mattie's house consists of two stories and an attic the first floor is 8 and 5 six feet tall the second floor is 8 & a half

Hitman42 [59]

This is telling you to do area and then add the two numbers you get

6 0

3 years ago

30 dogs to 20 cats lowest fraction

Romashka [77]

Answer:

Answer : 3/2

Step-by-step explanation:

30/20= 3/2

it is because we don't want the zero so that we can take it off.

Hope this help you!! :))

5 0

3 years ago

Using the numbers 2,0,1,9 in order what exoression do you make to equal 6

alexgriva [62]

Answer: $9-(0+1+2)$

Step-by-step explanation:

We have given the numbers = 2,0,1,9

We can use addition and subtraction operation to the given numbers such that the answer will be equals to 6.

We can add 2 ,0 and 1 and then subtract from 9 , we will get 6.

So the required expression can be

$9-(0+1+2)\\=9-(3)\\=9-3\\=6$

hence, the required expression can be $9-(0+1+2)$

6 0

3 years ago