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Alinara [238K]
3 years ago
15

Is 5.5 greater then 5.7

Mathematics
2 answers:
ivann1987 [24]3 years ago
3 0
No, it is .2 less than 5.7
Andrew [12]3 years ago
3 0
No it is smaller. Think of it in quarters. 50 cents (.50) is less than 75 cents (.75)
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Bobby earns $9 per hour plus commission. Last week he worked 32.5 hours
Nesterboy [21]

Answer:

Step-by-step explanation:

32.5*9=292.5

add the commission - $28.75

292.5+28.75= $321.25

8 0
2 years ago
Read 2 more answers
6. If m∠COD=8x+13, m∠BOC=3x-10, and m∠BOD=12x-6, find m∠BOD
Ahat [919]

Answer:

Step-by-step explanation:

Given

m∠COD=8x+13,

m∠BOC=3x-10, and

m∠BOD=12x-6

The following addition property is true;

<BOD = <BOC + <COD

Substitute

12x-6 = 3x-10+8x+13

12x-6 = 11x+3

12x-11x = 3+6

x = 9

Get <BOD

<BOD = 12x-6

<BOD = 12(9)-6

<BOD = 108-6

<BOD = 102°

4 0
3 years ago
If g(t) = sec(t), what is g(-3 π )?
borishaifa [10]
It should be g(-3π) = sec(-3π)

I hope that helped. 
3 0
4 years ago
Read 2 more answers
If the second term of a geometric sequence of real numbers is -2 and the fifth term is 16 then what is the fourteenth term?
Agata [3.3K]
<h3>Given</h3>

A geometric sequence such that ...

a_2=-2\quad\text{and}\quad a_5=16

<h3>Find</h3>

a_{14}

<h3>Solution</h3>

We can use the ratio of the given terms to find the common ratio of the sequence, then use that to find the desired term from one of the given terms. We don't actually need the common ratio (-2). All we need is its cube (-8).

a_2=a_1r^{(2-1)}=a_1r^1\\a_5=a_1r^{(5-1)}=a_1r^4\\a_{14}=a_1r^{(14-1)}=a_1r^13=a_5r^9\\\\\dfrac{a_5}{a_2}=\dfrac{a_1r^4}{a_1r^1}=r^3=\dfrac{16}{-2}=-8\\\\r^9=\left(r^3\right)^3=(-8)^3=-512\\a_{14}=a_5(-512)\\\\a_{14}=-8192

7 0
3 years ago
In which quadrant is the point (5,-2) located?
nevsk [136]
Quadrant Four (IV) since the x coordinate is a positive and the y coordinate is a negative.
7 0
3 years ago
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