There is an infinite amount of 10 digits numbers with at leas two 1s in it.
Answer:3(7)+2=23. 21+2=23
Step-by-step explanation:
If tan theta is -1, we know immediately that theta is in either Quadrant II or Q IV. We need to focus on Q IV due to the restrictions on theta.
Because tan theta is -1, the ray representing theta makes a 45 degree angle with the horiz axis, and a 45 degree angle with the negative vert. axis. Thus the hypotenuse, by the Pythagorean Theorem, tells us that the hyp is sqrt(2).
Thus, the cosine of theta is adj / hyp, or +1 / sqrt(2), or [sqrt(2)]/2
The secant of theta is the reciprocal of that, and thus is
2 sqrt(2)
---------- * ------------ = sqrt(2) (answer)
sqrt(2) sqrt(2)
6x2 + x - 7
= (6x + 7)(x - 1)
So, the answer is (6x + 7), or C.
One is 17.22 and the other is simply 2.
