The answer is
"
"
(Remember that the "(" dont mean nothing)
Therefore it would equal
1×1=1<span>×1=1</span>
4×4=16×4=64
Hope this helps!
<span>6/3+(-1/3)
</span><span>= 6/3-1/3
= 5/3
= 1 2/3</span>
Answer:
18 and 5
Step-by-step explanation:
if 'x' - is the length and 'y' - the width of the rectangle, then
2(x+y)=46 - perimeter of the original rectangle and 2(2x+(y+5))=66 - the perimeter of the new rectangle.
Finally, the length is x=5 and the width is y=18.
M>5=m>4
m>5 and m>7 are on line then m>5+m>7=180
by substituting
m>4+37=180
m>4=143
m>2=m>7=37
m>4=m>8
m<3+m>5=180
17) f(x) = 16/(13-x).
In order to find domain, we need to set denominator expression equal to 0 and solve for x.
And that would be excluded value of domain.
13-x =0
Adding x on both sides, we get
13-x +x = x.
13=x.
Therefore, domain is All real numbers except 13.
18).f(x) = (x-4)(x+9)/(x^2-1).
In order to find the vertical asymptote, set denominator equal to 0 and solve for x.
x^2 -1 = 0
x^2 -1^2 = 0.
Factoring out
(x-1)(x+1) =0.
x-1=0 and x+1 =0.
x=1 and x=-1.
Therefore, Vertical asymptote would be
x=1 and x=-1
19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)
We have degrees of numberator and denominator are same.
Therefore, Horizontal asymptote is the fraction of leading coefficents.
That is 7/2.
20) f(x)=(x^2+3x-2)/(x-2).
The degree of numerator is 2 and degree of denominator is 1.
2>1.
Degree of numerator > degree of denominator .
Therefore, there would no any Horizontal asymptote.
