All categories

3 years ago

Can someone plzz help me on thiss!

Mathematics

1 answer:

aev [14]3 years ago

5 0

Answer:

Step-by-step explanation:

because it goes up constantly by 12

You might be interested in

If two angles are complementary angles and they measure m ∠1=(x + 5) and m∠2=(5x + 13). Find x and the measure for both an

Korolek [52]

5X+13+X+5=90°(SUM OF COMPLEMENTRY ANGLE IS EQUAL TO 90°)

6+18=90°

6X=90°-18°

X=72°/6

X=12 °ANSWER

6 0

3 years ago

A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60

Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let $c(t)$ is the amount of chemical in the take at t time.

Now find the rate of change of chemical flow during the first 20 minutes.

$\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt$

$\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0$

$\int\limits^{20}_{0} {c'(t)} \, dt =3600+600$

$\int\limits^{20}_{0} {c'(t)} \, dt =4200$

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0

3 years ago

What is a horseshoe crab?

Yanka [14]

Horseshoe crabs are marine and brackish water arthropods. They live primarily in and around shallow coastal waters on soft sands.

5 0

3 years ago

The midpoint of UV is point W. What are the coordinates of point V?

madreJ [45]

Since you don't provide the coordinates of the point W, I will help you in a general form anyway. In the Figure below is represented the segment that matches this problem. We have two endpoints U and V. So, by using the midpoint formula we may solve this problem:

$Midpoint=W=W(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})=W(x_{3}, y_{3}) \\ \\ where:\\ \ U=U(x_{1}, y_{1}) \ and \ V=V(x_{2}, y_{2}) \\ \\ and: \\ x_{3}=\frac{x_{1}+x_{2}}{2} \\ y_{3}=\frac{y_{1}+y_{2}}{2}$

Therefore:

$x_{2}=2x_{3}-x_{1} \\ y_{2}=2y_{3}-y_{1}$

So we know $x_{3} \ and \ y_{3}$ but we also must know $x_{1} \ and \ y_{1}$

Finally, knowing the points U and W we can find the endpoint V.

7 0

3 years ago

Read 2 more answers

H(x)=1/8x^3-x^2 Over which interval does h have a positive average rate of change?

lara31 [8.8K]

Answer:

$(-\infty,0)\cup(\frac{16}{3},\infty)\\That \ is x\frac{16}{3}$

Step-by-step explanation:

$h(x)=\frac{1}{8}x^{3} -x^{2} \\\\Differentiate \ h(x) \ with \ respect \ to \ x\\h'(x)=\frac{3}{8}x^{2} -2x$

For positive rate of change $h'(x)>0$

$\frac{3}{8} x^{2} -2x>0\\x(\frac{3}{8}x-2)>0\\\\ When \ x0 \ (multiplication \ of \ two \ positives \ is \ positive)\\\\h'(x)>0 \ when \ x\frac{16}{3} \\\\$

6 0

3 years ago