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4 years ago

Solve triangle ABC if A = 50°, a = 10, and b = 20. If no triangle exists, explain why.

Mathematics

1 answer:

Dahasolnce [82]4 years ago

6 0

Answer:

No triangle exist

Step-by-step explanation:

step 1

Find the measure of angle B

Applying the law of sines

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{10}{sin(50^o)}=\frac{20}{sin(B)}$

$sin(B)=20(sin(50^o))/10$

$sin(B)=1.532$

Remember that

The maximum value of the sine is 1

therefore

No triangle exist

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Unit 8 right triangle and trigonometry homework 5 trigonometry: finding sides and angles solve for x round to the nearest tenth.

zmey [24]

Answer:

5. x = 25.6

6. x = 11.0

7. x = 41.8°

8. x = 64.2°

9. x = 12.8°

10. x = 51.3°

Step-by-step explanation:

Let's find the x value for each triangle.

For point 5

We have:

x: is the opposite cathetus to 52°

20: is the adjacent cathetus to 52°

52°: is the angle

We can find "x" with the following trigonometric function:

$tan(52) = \frac{x}{20}$

$x = tan(52)*20 = 25.6$

For point 6

We have:

x: is the hypotenuse

5: is the opposite cathetus to the given angle

27°: is the angle

To find "x" we need to use the trigonometric function:

$sin(27) = \frac{5}{x}$

$x = \frac{5}{sin(27)} = 11.0$

For point 7

We know:

x°: is the angle

6: is the hypotenuse

4: is the opposite cathetus to x°

Hence, x is:

$sin(x) = \frac{4}{6}$

$x = sin^{-1}(\frac{4}{6}) = 41.8$

For point 8

We have:

x°: is the angle

14: is the adjacent cathetus to x°

29: is the opposite cathetus to x°

To calculate "x" we need to use the trigonometric function tan(x):

$tan(x) = \frac{29}{14}$

$x = tan^{-1}(\frac{29}{14}) = 64.2$

For point 9

We have:

x°: is the angle

54: is the hypotenuse

12: is the opposite cathetus to x°

We can use sin(x) to solve for x:

$sin(x) = \frac{12}{54}$

$x = sin^{-1}(\frac{12}{54}) = 12.8$

For point 10

We have:

x°: is the angle

40: is the hypotenuse

25: is the adjacent cathetus to x°

We need to use cos(x) to solve for x:

$cos(x) = \frac{25}{40}$

$x = cos^{-1}(\frac{25}{40}) = 51.3$

I hope it helps you!

5 0

3 years ago

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Montano1993 [528]

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7 0

3 years ago

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lyudmila [28]

Answer:

x = 6, ∠ B = 126°

Step-by-step explanation:

∠ A and ∠ B are alternate angles and congruent, so

8x + 78 = 2x + 114 ( subtract 2x from both sides )

6x + 78 = 114 ( subtract 78 from both sides )

6x = 36 ( divide both sides by 6 )

x = 6

Then

∠ B = 2x + 114 = 2(6) + 114 = 12 + 114 = 126°

7 0

3 years ago

N/-2 > 4 How do you Solve it

3241004551 [841]

N/-2 > 4 is same as N/-2 * -2 > 4* -2
So, N < -8 (N should be always less than -8)

8 0

3 years ago

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Anastasy [175]

Answer:

D) 9000 m³

Step-by-step explanation:

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8 0

3 years ago