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kondor19780726 [428]

4 years ago

7

A basketball player attemps 15 free throws in a game. He makes 9 of the attempted free throws. Which ratio describes the number

of free throws the player made to the number of attempted free throws? 1.)3/5 2.)5/3 3.)2/5 4.)5/2

1 answer:

Ber [7]4 years ago

5 0

Answer:

1) 3: 5

Step-by-step explanation:

Hope this helps!!! :)

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A cosmetic company makes three bottles of scented lotion using the recipe shown. Each bottle holds a different amount of lotion.

seropon [69]

Answer:

Part 1) Bottle 1 (vanilla=1,almond=3,pineapple=4)

Part 2) Bottle 2 (vanilla=2,almond=6,pineapple=8)

Part 3) Bottle 3 (vanilla=1 1/2,almond=4 1/2,pineapple=6)

Step-by-step explanation:

Let

x ----> the amount of vanilla sent

y ----> amount of almond sent

z ----> the amount of pineapple sent

we know that

$x:y:z=\frac{1}{8}:\frac{3}{8}:\frac{1}{2}$

so

$\frac{x}{y}=\frac{1}{8}:\frac{3}{8}$

$\frac{x}{y}=\frac{1}{3}$

$x=\frac{y}{3}$ -----> equation A

$\frac{x}{z}=\frac{1}{8}:\frac{1}{2}$

$\frac{x}{z}=\frac{1}{4}$

$x=\frac{1}{4}z$ -----> equation B

$\frac{y}{z}=\frac{3}{8}:\frac{1}{2}$

$\frac{y}{z}=\frac{3}{4}$

$y=\frac{3}{4}z$ -----> equation C

Part 1) Bottle 1

vanilla=?

almond=?

pineapple=4

we have

$z=4$

<em>Find the value of x</em>

substitute the value of z in equation B

$x=\frac{1}{4}(4)$

$x=1$

<em>Find the value of y</em>

substitute the value of z in equation C

$y=\frac{3}{4}(4)$

$y=3$

therefore

<em>Bottle 1</em>

vanilla=1

almond=3

pineapple=4

Part 2) Bottle 2

vanilla=?

almond=6

pineapple=?

we have

$y=6$

<em>Find the value of x</em>

substitute the value of y in equation A

$x=\frac{6}{3}=2$

<em>Find the value of z</em>

substitute the value of x in equation B

$2=\frac{1}{4}z$

solve for z

$z=8$

therefore

<em>Bottle 2</em>

vanilla=2

almond=6

pineapple=8

Part 3) Bottle 3

vanilla=1 1/2

almond=?

pineapple=?

we have

$x=1\frac{1}{2}$

convert to an improper fraction

$x=1\frac{1}{2}=\frac{1*2+1}{2}=\frac{3}{2}$

<em>Find the value of y</em>

substitute the value of x in equation A

$\frac{3}{2}=\frac{y}{3}$

$y=\frac{9}{2}$

convert to mixed number

$y=\frac{9}{2}=\frac{8}{2}+\frac{1}{2}=4\frac{1}{2}$

<em>Find the value of z</em>

substitute the value of x in equation B

$\frac{3}{2}=\frac{1}{4}z$

$z=6$

therefore

<em>Bottle 3</em>

vanilla=1 1/2

almond=4 1/2

pineapple=6

5 0

3 years ago

Read 2 more answers

Can u help me with number 2-4 plz now!!

Montano1993 [528]

Number two. Equals 4

4 0

3 years ago

Which graph does NOT represent a function?<br> A)<br> A<br> B)<br> B<br> C)<br> С<br> D)<br> D

IRISSAK [1]

Answer:

(B)

Step-by-step explanation:

it is an undefined

7 0

3 years ago

There was a triangle ABC with sides 15, 20, and 10. One of the sides of a triangle, which is similiar to ABC is 60. What are the

wlad13 [49]

Answer:

The possible pairs of sides are 90 and 120, 30 and 45, and 80 and 40.

Step-by-step explanation:

We know that 60 is a multiple of 15, 20, and 30, so we multiply by each factor to find all possible pairs: 10x6=60, 20x6=120, and 15x6=90, that gives your first pair, <u>90 and 120</u>.

We have now multiplied our first factor, 6. Now we need to multiply our second factor, 3: 20x3=60, 15x3=45, and 10x3=30. That gives your second pair, <u>30 and 45</u>.

Finally, we need to multiply by our 3rd factor, 4: 15x4=60, 20x4=80, and 10x4=40. That gives you your final possible pair, <u>80 and 40</u>.

I hope this helps :-)

3 0

3 years ago

Which of the following is NOT true of the confidence level of a confidence interval? Choose the correct answer below. A. The co

Grace [21]

Answer:

<em>There is a 1-a chance, where a is the complement of the confidence level, that the true value of p will fall in the confidence interval produced from our sample.</em> ( B )

Step-by-step explanation:

Confidence level depicts the probability that the confidence interval actually contains the values of p ( true values of P ) hence

<em>There is a 1-a chance, where a is the complement of the confidence level, that the true value of p will fall in the confidence interval produced from our sample</em> Is a complete misinterpretation of the confidence interval therefore it is NOT true

8 0

3 years ago