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Nataly_w [17]
2 years ago
9

What is 68.52 rounded to the nearest whole number? A. 68 B. 68.5 C. 68.6 D. 69

Mathematics
2 answers:
SCORPION-xisa [38]2 years ago
4 0
I'm in between D in B but I think B is your best answer
vodomira [7]2 years ago
3 0
The answer is D. You round up
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The current price of each share of a technology company is $135, If this represents a 16.2% increase over last year what was the
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The answer is $116.18. 135 is 116.2% of the previous year.
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2 years ago
Write the complex number in the form a + bi.<br> 3(cos 60° + i sin 60°)
hram777 [196]

Answer:

The complex number in the form of a + b i is 3/2 + i √3/2

Step-by-step explanation:

* Lets revise the complex number in Cartesian form and polar form

- The complex number in the Cartesian form is a + bi

-The complex number in the polar form is r(cosФ + i sinФ)

* Lets revise how we can find one from the other

- r² = a² + b²

- tanФ = b/a

* Now lets solve the problem

∵ z = 3(cos 60° + i sin 60°)

∴ r = 3 and Ф = 60°

∵ cos 60° = 1/2

∵ sin 60 = √3/2

- Substitute these values in z

∴ z = 3(1/2 + i √3/2) ⇒ open the bracket

∴ z = 3/2 + i √3/2

* The complex number in the form of a + b i is 3/2 + i √3/2

6 0
2 years ago
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Marisol is in a bathtub that is shaped like a rectangular prism, about 5 ft long, 2 ft wide, and 1 ft deep. She is drinking hot
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Solve the following question ​
nydimaria [60]

9514 1404 393

Answer:

  π/3

Step-by-step explanation:

The given integral does not exist. We assume there is a typo in the upper limit, and that you want the integral whose upper limit is (√3)/2.

It is convenient to make the substitution ...

  x = sin(y) . . . . so, y = arcsin(x)

 dx = cos(y)·dy

Then the integral is ...

  \displaystyle\int_0^{\sqrt{3}/2}{\dfrac{\cos{y}}{\sqrt{1-\sin^2{y}}}}\,dy=\int_0^{\sqrt{3}/2}{dy}=\left.\arcsin{x}\right|\limits_0^{\sqrt{3}/2}\\\\=\arcsin{(\sqrt{3}/2)}=\boxed{\dfrac{\pi}{3}}

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2 years ago
Anybody there to talk​
Anon25 [30]

Answer:

yeah think so? have u done it?

5 0
2 years ago
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