Answer with explanation:
In Δ ABC and ΔD BC
∠A=∠D-------Given
∠ABC=∠DCB-------Each being 90° given in the Diagram.
Side, BC is Common.
⇒⇒Δ ABC ≅ ΔD BC-------[AAS]
When two triangles are congruent , their areas are equal.
So, Area(ABC)=Area (DCB)
Option B :⇒ A AS
<span>1st piece: x feet
2nd piece: 8-x feet
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Use the "x" piece to form a circle:
Circumference = "x".
2(pi)*radius = x
radius = x/(2pi)
So, Area = pi[x/(2)]^2 = x^2/(4pi) = (1/4pi)x^2
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Use the 10-x piece to form square:
side = (1/4pi)(10-x)
Area = side^2 = (1/16)(10-x)^2
Hope this helps! :)</span>
