Answer:
Kindly check explanation
Step-by-step explanation:
Given the data :
Technician __Shutdown
Taylor, T___4
Rousche, R _ 3
Hurley, H__ 3
Huang, Hu___2
Gupta, ___ 5
The Numbe of samples of 2 possible from the 5 technicians :
We use combination :
nCr = n! ÷ (n-r)!r!
5C2 = 5!(3!)2!
5C2 = (5*4)/2 = 10
POSSIBLE COMBINATIONS :
TR, TH, THu, TG, RH, RHu, RG , HHu, HG, HuG
Sample means :
TR = (4+3)/2 = 3.5
TH = (4+3)/2 = 3.5
THu = (4+2) = 6/2 = 3
TG = (4 + 5) = 9/2 = 4.5
RH = (3+3) = 6/2 = 3
RHu = (3+2) /2 = 2.5
RG = (3 + 5) = 8/2 = 4
HHu = (3+2) = 2.5
HG = (3+5) = 8/2 = 4
HuG = (2+5) / 2 = 3.5
Mean of sample mean (3.5+3.5+3+4.5+3+2.5+4+2.5+4+3.5) / 10 = 3.4
Population mean :
(4 + 3 + 3 + 2 + 5) / 5 = 17 /5 = 3.4
Population Mean and mean of sample means are the same.
This distribution should be approximately normal.
Answer:
375 sheep.
Step-by-step explanation:
To find 1/4 of 1500, you must divide the number by the denominator of the fraction.
1500 ÷ 4 = 375
Answer:
in confused on what the question is asking is it multiple questions
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Step-by-step explanation:
∆FGE ~ ∆ JKL
i.e, Angle FGE = angle JKL = 63°
and angle GEF = angle KLJ = 29°
also, angle GFE = angle KJL = 88°
so, the ∆FGE ~ ∆ JKL by AA property of similarity !!
• not other options because if we take corresponding angle they are not equal
For eg. for ∆ EFG ~ ∆ JKL
the angle EFG must be equal to angle JKL to be similar !!
but they are not equal !!
so, they are not similar !!
and such ,all other options except 3rd is wrong !!
Answer:(x,y)=(2.5,1)
Step-by-step explanation:
Given
thus on comparing
2x+y=6------1
On comparing exponent of 2
------2
we get x=2.5
substitute x in 1
y=1
(x,y)=(2.5,1)
