Answer:
C
Step-by-step explanation:
You start with 3 and subtract a number
keeping in mind that 4 months is not even a year, since there are 12 months in a year, 4 months is then 4/12 years.
let's assume is simple interest.
![\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$34300\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ t=years\to \frac{4}{12}\dotfill &\frac{1}{3} \end{cases} \\\\\\ A=34300\left[ 1+(0.035)\left( \frac{1}{3} \right) \right]\implies A= 34300(1.011\overline{6})\implies A=34700.1\overline{6}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%20%5C%2434300%5C%5C%20r%3Drate%5Cto%203.5%5C%25%5Cto%20%5Cfrac%7B3.5%7D%7B100%7D%5Cdotfill%20%260.035%5C%5C%20t%3Dyears%5Cto%20%5Cfrac%7B4%7D%7B12%7D%5Cdotfill%20%26%5Cfrac%7B1%7D%7B3%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D34300%5Cleft%5B%201%2B%280.035%29%5Cleft%28%20%5Cfrac%7B1%7D%7B3%7D%20%5Cright%29%20%5Cright%5D%5Cimplies%20A%3D%2034300%281.011%5Coverline%7B6%7D%29%5Cimplies%20A%3D34700.1%5Coverline%7B6%7D)
The temperature at midnight would be -14*F. Subtract 10 from -4 and you get -14*F
Can't see the figure, but the basic way to solve this problem is to use the formula for volume of a pyramid which is (length * width * height )/3. Slant height is just the square root of ((length/2)2 + height2) recognizing that there is a right triangle there. Since slant height increased by 4 cm when its height increased by 2cm, you know that the length/2 term had to increase by the square root of 12 (22+root(12)2) = 42=16. From there you can figure out the rest pretty readily.
Answer:
No.
Step-by-step explanation:
A scale copy would see that both the x and y amount would be scaled proportionally. In this case, the x goes across 5 for figure A, and does the same for Figure B. On the other hand, the scaling for y is 2 for figure A, while it is 5 for figure B.
If it is a scale copy then.
If Figure A have the scaling of: 3, 5, 5, x, then Figure B, if given one scale of 5, should have
3:5
5:8.33
5:8.33
x:(x * ~1.67)
Therefore, the scaling is off.
