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AlexFokin [52]
2 years ago
11

One afternoon in January, the temperature outside was -4*F. By midnight, the temperature had dropped by 10*F. what was the tempe

rature at midnight?
Brainliest
Mathematics
1 answer:
loris [4]2 years ago
3 0
The temperature at midnight would be -14*F. Subtract 10 from -4 and you get -14*F
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7.5 mph

Step-by-step explanation:

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3 0
3 years ago
2 8 −10−15÷3=2, start superscript, 8, end superscript, minus, 10, minus, 15, divided by, 3, equals
Sergio039 [100]

Answer:

241

Step-by-step explanation:

Given the equation to evaluate :

2^8 −10−15÷3

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From BODMAS principle, we evaluate the divison before subtraction :

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= 241

8 0
2 years ago
Need help, and please answer
masya89 [10]

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Step-by-step explanation:

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6 0
3 years ago
Which table does NOT show a proportional relationship?<br> 1 point<br><br> A<br> B<br> C<br> D
Luda [366]
The answer is Either ‘A’ or ‘D’
8 0
3 years ago
Read 2 more answers
∠1 ​ and ∠2 are supplementary. ∠1=124°∠2=(2x+4)° Select from the drop down menu to correctly answer the question.
Alex_Xolod [135]
Remark
Supplementary angles add up to 180o. 

Givens
<1 = 124
<2 = 2x + 4

I imagine you are looking for either x or <2. 

Equation
<1 + <2 = 180          Substitute the givens
124 + 2x + 4 = 180  Collect like terms on the left.
128 + 2x = 180         Subtract 128 from both sides
2x = 180 - 128          Collect like terms on the right   
2x = 52                     divide by 2
x = 52/2
x = 26 <<<<<<<<< answer

<1 = 124
<2 = 2x + 4 = 2*26 + 4
<2 = 52 + 4
<2 = 56  <<<<<<<< answer

We need choices if you want an exact answer.

3 0
3 years ago
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