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Alchen [17]
3 years ago
14

When performing the calculation 34.530 g + 12.1 g + 1 222.34 g, the final answer must have:

Mathematics
1 answer:
stepladder [879]3 years ago
6 0

<u>Answer:</u> The final answer must have only one decimal place.

<u>Step-by-step explanation:</u>

Significant figures are defined as the figures present in a number that expresses the magnitude of a quantity to a specific degree of accuracy.

We are given:

An addition problem having values (34.530 g + 12.1 g + 1222.34 g)

<u>The rule that is applied for the addition and subtraction is:</u>

The least precise number present after the decimal point determines the number of significant figures in the answer.

For the given problem, the least precise number after the decimal is '1'

Evaluating the value: (34.530 g + 12.1 g + 1222.34 g) = 1268.97 ≈ 1269.0

Hence, the final answer must have only one decimal place.

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Aleksandr-060686 [28]

Answer:  " 2x (2x - 1) (x + 1) " .

______________________________________

Step-by-step explanation:

______________________________________

Given:  

  f(x)   =  9x³ + 2x² − 5x  + 4  ;

  g(x)  =  5x³ − 7x + 4 ;

______________________________________

What is:  f(x) − g(x) ?

______________________________________

Plug in:  " 9x³ + 2x² − 5x + 4 "  for:  " f(x) " ;

    and:   " (5x³ − 7x + 4) " ;  for:  "g(x)" ;

______________________________________

→  " f(x) − g(x)   =  

   

       " 9x³ + 2x² − 5x + 4  − (5x³ − 7x + 4) "  .

______________________________________

Rewrite this expression as:

 →  " 9x³ + 2x² − 5x + 4  − 1(5x³ − 7x + 4) "  .

 →   {since:  " 1 " ;  multiplied by "any value" ;  is equal to that same value.}.

______________________________________

Now, let us example the following portion of the expression:

______________________________________

 "  − 1(5x³ − 7x + 4) "

_____________________________________

Note the "distributive property"  of multiplication:

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    →   a(b + c) = ab + ac ;

______________________________________

Likewise:

     →  a(b + c + d) = ab + ac + ad .

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As such:

______________________________________

    →  "  − 1(5x³ − 7x + 4)  "  ;

______________________________________

             =   (-1 * 5x³) + (-1 * 7x) + (-1 * 4) ;

             =  - 5x³  +  (-7x)  +  (-4)  ;

             =   - 5x³  − 7x − 4  ;

_____________________________________

Now, add the "beginning portion of the expression" ; that is:

  " f(x) " ;  to the expression ;  which is:

                        →   9x³ + 2x² − 5x  +  4  ;

 →  as follows:  

_______________________________________

 →  9x³ + 2x² − 5x  +  4 − 5x³ − 7x − 4  ;

 →  {Note that the:  " - " sign; that is;

       the "negative sign", in the term:  " -5x³ " ;

       becomes a: " − " sign; that is; a "minus sign" .}.

______________________________________

Now, combine the "like terms" of this expression; as follows:

  + 9x³  −  5x³  =  + 4x³ ;

 − 5x − 7x  =  − 2x ;

 + 4 − 4 = 0 ;

______________________________________

and we have:

______________________________________

 →     " 4x³  +  2x²  − 2x ".

______________________________________

Now, to write this answer in "factored form" :

Note that among all 3 (three) terms in this expression, each term has a factor of "2" .  The lowest coefficient among these 3 (three) terms is "2" ;  so we can "factor out" a "2".  

Also, each of the 3 (three) terms in this fraction is a coefficient to a variable.  That variable takes the form of "x".  The term in this expression  with the variable, "x";  with the lowest degree has the variable: "x" (i.e. "x¹ = x" ) ;  so we can "factor out a "2x" (rather than just the number, "2".).

So, by factoring out a "2x" ;  take the first term [among the 3 (three) terms in the expression] —which is:  "4x³ " .

2x * (?)  = 4x³  ?  ;'

↔  \frac{4x^3}{2x} = ? ;

→  4/2 = 2 ;

\frac{x^{3}}{x} = \frac{x^3}{x^1}  = x^{(3-1)} =  x^{2} ;  

As such:   2x * (2x²)  =  4x³ ;

___________________________________________

Now, by factoring out a "2x" ;  take the second term [among the 3 (three) terms in the expression] — which is:  "2x² " .

2x * (?) = 2x²  ? ;

↔   \frac{2x^{2}}{2x} =  ?

→  2/2 = 1 ;

→  \frac{x^{2}}{x} = \frac{x^2}{x^1}= x^{(2-1)} } = x^1 = x ;

As such:  2x * (x) = 2x²

__________________________________________

Now, by factoring out a "2x" ;  take the third term [among the 3 (three) terms in the expression] — which is:  " − 2x " .

2x * (?) =  - 2x ;

↔  \frac{-2x}{2x} = -1 ;

As such:  2x * (-1) =  − 2x .  

__________________________________________

So:

__________________________________________

Given the simplified expression:

 →     " 4x³  +  2x²  − 2x " ;

We can "factor out' a:  " 2x " ;  and write the this answer is: "factored form" ; as:

__________________________________________

  "2x (2x²  +  x  −  1 ) . "

Now, we can further factor the:

    " (2x²  +  x  −  1) " ; portion;

Note:  "(2x² + x - 1)" =

2x² + 2x - 1x -1 = (2x -1) + x (2x - 1 ) =

(2x - 1)  ( x + 1)

_______________________________________

Now, bring down the "2x" ; and write the Full "factored form" ; as follows:

_______________________________________

    →   " 2x (2x - 1) (x + 1) "  .

_______________________________________

Hope this helps!

 Wishing you the best!

_______________________________________

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