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BartSMP [9]
3 years ago
8

Solve the inequality. ​m−4>12

Mathematics
1 answer:
alexgriva [62]3 years ago
4 0

Good evening

Answer:

<h2>m > 16</h2>

Step-by-step explanation:

m−4>12

then (by adding 4 to both sides of the inequality we get)

m−4+4 > 12+4

then

m > 16

solution as interval: [16 , +∞)

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Can someone please help me on this
docker41 [41]

Answer:

• The function is a linear function

• The function changes at a constant rate

Step-by-step explanation:

A graph of the function shows it to be a straight line (linear function). Such a function always changes at a constant rate. The line goes downward to the right, so the function is a decreasing function.

___

"changes at a constant rate" and "linear function" are two different ways of saying the same thing: the graph of the function is a straight line.

3 0
3 years ago
F(x)=-5x+2 and g(x)=1/2x+4 find f(g(12))
skad [1K]

Answer:

- 48

Step-by-step explanation:

If you want to learn more about this concept, it's called composition of functions.

First, you plug in g(x) as if it were x into f(x).

f(g(x))= -5 (1/2x + 4) + 2

= -5/2x - 20 + 2

= -5/2x - 18

Then, plug in the value given, as x.

= -5/2 (12) - 18

= -30 - 18

= - 48

I hope this helped!

3 0
3 years ago
Complete the sentences below the radius of a circle is _____ the length of its diameter. the diameter of a circle is ______ the
son4ous [18]

Answer:

Half;  twice

Step-by-step explanation:

In a circle, the radius is said to be the distance from the center of the circle to any point on the edge of the circle, it is denoted as "r". The radius is called a radii if it is more than one.. The radius of a circle is half the length of the diameter of a circle because the diameter of a circle is the distance of the line that passes through the center of a circle touching both edges of the circle. It is denoted as "d".

Thus,

2r = d

r = d/2

For example, if the radius of a circle is 10cm, the diameter of the circle will be calculated as: d = 2 * 10 = 20cm. Which means if the radius is 10cm, diameter will be 20cm.

Therefore, the radius of a circle is half the length of its diameter. the diameter of a circle is twice the length of its radius

5 0
3 years ago
Need help finding the domain and range
pogonyaev

Here are a few things you'll need to know for this question:

  • Domain: <u>The list of x-values that are possible on a line.</u>
  • Range: <u>The list of y-values that are possible on a line.</u>
  • Interval Notation: <u>Shows the domain/range using the endpoints</u>. Brackets mean that the endpoint is included, parentheses mean the endpoint is excluded. Ex: (2,10]. 2 is excluded, 10 is included.
  • Closed Circles: <u>The endpoint is included.</u>
  • Open Circles: <u>The endpoint is excluded.</u>

So firstly, let's look at the domain. We see that there is a closed circle at x = -2 and an open circle at x = 5. Using what we know, <u>the interval notation of the domain is [-2,5).</u>

Next, let's look at the range. We see that there is a closed circle at y = -5 and an open circle at y = 2. Using what we know, <u>the interval notation of the range is [-5,2).</u>

3 0
3 years ago
Given: ∆ABC –iso. ∆, m∠BAC = 120°
lidiya [134]

Answer: P\triangle ADH = (a+b+\sqrt{a^2+b^2} ) unit

Step-by-step explanation:

Since Here Δ ABC is a isosceles triangle.

Also, AH\perp BC and HD\perp AC

Thus, ∠ ADH = 90°

That is, Δ ADH is the right angle triangle.

In which, AD = a unit and HD = b unit

And, By the definition of Pythagoras theorem,

AH^2 = HD^2 + AD^2

⇒ AH^2 = a^2 +b^2

⇒ AH = \sqrt{a^2+b^2}

Since, the perimeter of a triangle = sum of the all sides of the triangle.

Therefore, perimeter of ΔADH = AD + DH + AH

= a + b + \sqrt{a^2+b^2} unit

4 0
3 years ago
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