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3 years ago

15

A sporting goods store randomly sampled three groups of 100 customers on what their favorite spectator sport is. The data shows

the results of the three samples. Baseball Basketball Football Total Group 1 27 28 45 100 Group 2 26 28 46 100 Group 3 30 26 44 100 The sporting goods store has 1225 customers one weekend. Based on the samples, what is a reasonable estimate of the number of people who will prefer to watch football? Enter your answer rounded to the nearest whole number in the box.

2 answers:

katen-ka-za [31]3 years ago

4 0

Answer:

A reasonable estimate of the number of people who will prefer to watch football is:

551

Step-by-step explanation:

Baseball Basketball Football Total

Group 1 27 28 45 100

Group 2 26 28 46 100

Group 3 30 26 44 100

Now we have from the table that the number of people who prefer to watch football is close to 45.

Hence, out of 1225 people a reasonable estimate of the number of people who prefer to watch football is calculated as:

$=\dfrac{45}{100}\times 1225\\\\\\=0.45\times 1225\\\\=551.25$

Hence, to the nearest whole number it is: 551

-BARSIC- [3]3 years ago

3 0

Answer:

it is 551!

Step-by-step explanation:

I just took the test! Please give me the brainliest!

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Write a linear function f with f(0)=7 and f(3)=1.

choli [55]

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a = ( 0 , 7 ) & b = ( 3 , 1 )

First need to find the slope using the following equation :

$slope = \frac{y(b) - y(a)}{x(b) - x(a)} \\$

$slope = \frac{1 - 7}{3 - 0} \\$

$slope = \frac{ - 6}{3} \\$

$slope = - 2$

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We have following equation to find the point-slope form of the linear functions using the slope and one of the through points .

$y - y(0) = m \times ( \: x - x(0) \: )$

$x(0) = x - coordinate \: \: of \: \: through \: \: point \\$

$y(0) = y - coordinate \: \: of \: \: through \: \: point \\$

$m = slope$

I choose point (( a )) to put in the equation.

$y - 7 = - 2 \times (x - 0)$

$y - 7 = - 2x + 0$

$y - 7 = - 2x$

Add sides 7

$y - 7 + 7 = - 2x + 7$

$y = - 2x + 7$

This the slope-intercept form .

Done...

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2 years ago

A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow

Mrrafil [7]

Answer:

$\displaystyle \frac{54}{5405}$ .

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

$\displaystyle \left(50\atop 5\right) = 2,118,760$ .

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

$\displaystyle \left( 28\atop 2\right) = 378$ .

Number of ways to choose 3 green candies out of a batch of 8:

$\displaystyle \left(8\atop 3\right)=56$ .

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

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The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:

$\displaystyle \frac{21,168}{2,118,760} = \frac{54}{5405}$ .

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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