A real-life situation that can be modeled by the expression 1/4 x 2/3 .

How do you find the Radius of a cylinder?

oksano4ka [1.4K]

If you know the volume and the height of a cylinder, you can find its radius by using the formula for the volume of a cylinder.Know the Formula for the Volume of a Cylinder. ...Solve for the Radius (r) ...Plug in the Values for Height (h) and Volume (V) and Calculate.

3 0

3 years ago

Write in standard form: y=2/3x+1

garri49 [273]

Standard form : Ax + By = C

y = 2/3x + 1
-2/3x + y = 1....multiply by -3
2x - 3y = -3 <=== standard form

3 0

3 years ago

Suppose a random sample of 50 college students are asked to measure the length of their right foot in centimeters. A 95% confide

hichkok12 [17]

Answer:

A 99% confidence interval will be wider than a 95% confidence interval

Step-by-step explanation:

From the question we are told that

The 95% confidence interval for for the mean foot length for students at the college is found to be 21.709 to 25.091 cm

Generally the width of a confidence interval is dependent on the margin of error.

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

From the above equation we see that

$E \ \ \alpha \ \ Z_{\frac{\alpha }{2} }$

Here $Z_{\frac{\alpha }{2} }$ is the critical value of the half of the level of significance and this value increase as the confidence level increase

Now if a 99% confidence level is used , it then means that the value of

$Z_{\frac{\alpha }{2} }$ will increase, this in turn will increase the margin of error and in turn this will increase the width of the confidence interval

Hence a 99% confidence interval will be wider than a 95% confidence interval

5 0

3 years ago

Consider the sequence: 12, 17, 22, ... , ... , .... What is the 405th term of this sequence?

Mice21 [21]

A_n= a₁+(n-1)d

a₁ first term

n terms

d distance between each value

a_n= 12+(405-1)(5)=2032

7 0

3 years ago

Read 2 more answers

There are 412 students and 20 teachers taking buses on a trip to a museum. Each bus can seat a maximum of 48. Which inequality g

-BARSIC- [3]

The inequality $\mathrm{b} \geq \frac{\text { total number of travelers }}{\text { capacity of each bus }}$ gives the least number of buses, b, needed for the trip. The least number of buses is 9

Solution:

Given that, There are 412 students and 20 teachers taking buses on a trip to a museum.

Each bus can seat a maximum of 48.

We have to find which inequality gives the least number of buses, b, needed for the trip?

Now, there are 412 students and 20 teachers, so in total there are 412 + 20 = 432 travelers

The number of buses required “b” is given as:

$\text { (b) } \geq \frac{\text { total number of travelers }}{\text { capacity of each bus }}$

$\text { So, number of buses required } \geq \frac{432}{48}$

Number of buses required ≥ 9 buses.

But least number will be 9 from the above inequality.

Hence, the inequality $\mathrm{b} \geq \frac{\text {total number of travelers}}{\text {capacity of each bus}}$ gives least count of busses and least count is 9.

6 0

3 years ago