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3 years ago

9

The admission fee at a small to the school play is $1.50 for children (x) and $4.00 for adults (y). On opening night, the revenu

e for the play was $5,050. Write an equation to represent the revenue on opening night.

1 answer:

Alecsey [184]3 years ago

5 0

Answer:

1.50x + 4.00y =5,050

Step-by-step explanation:

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I don't quite understand the LCD and the unlike denominators properly. May someone explain it, please.

Whitepunk [10]

Hey!

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LCD stands for Lowest Common Denominator.

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Explanation:

So let's say we have the equation 1/9 * 16/27

We want to find the LCD of both fractions. To find the LCD of both fractions find a the lowest common denominator in both fractions.

In this equation the lowest common denominator is 27 because 9 can go in 27 and 27 can go into itself. Se basically 27 is the lowest possibly common denominator both fractions can get to.

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Hope This Helped! Good Luck ;)

5 0

3 years ago

Find thhe remainder when 7^203 is divided by 4

Aleksandr [31]

Using the square-and-multiply approach, we have

$7^{203}=7\times(7^{101})^2$
$7^{101}=7\times(7^{50})^2$
$7^{50}=(7^{25})^2$
$7^{25}=7\times(7^{12})^2$
$7^{12}=(7^6)^2$
$7^6=(7^3)^2$
$7^3=7\times7^2$

and so, using the property that, if $a_1\equiv b_1\mod n$ and $a_2\equiv b_2\mod n$ , then $a_1a_2\equiv b_1b_2\mod n$ , we get

$7\equiv3\mod4$
$7^2\equiv9\equiv1\mod4$
$7^3\equiv7\times1\equiv7\equiv3\mod4$
$7^6\equiv9\equiv1\mod4$
$7^{12}\equiv1\mod4$
$7^{25}\equiv7\times1\equiv7\equiv3\mod4$
$7^{50}\equiv9\equiv1\mod4$
$7^{101}\equiv7\times1\equiv7\equiv3\mod4$
$7^{203}\equiv7\times9\equiv3\times1\equiv3\mod4$

4 0

3 years ago

Rectangle A measures 9 in by 3 in in rectangle B is a scaled copy of rectangle A. all measurements

taurus [48]

Answer:
3
Step-by-step explanation:
2 +2 =4 -1 is 3

5 0

3 years ago

−15(x−4)=−2<br><br> Hurry! Brainliest if right!

devlian [24]

Step-by-step explanation:

The answer is 62/15.

I can't explain it bc I'm taking a test rn but still-

6 0

3 years ago

Read 2 more answers

Sandy multiplies 2*5*7*2*5*7*2*5 and writes the product as a counting number.What is the sum of the digits of this counting numb

DiKsa [7]

Answer:

The sum of the digit of the product is 13

Step-by-step explanation:

Given

$2*5*7*2*5*7*2*5$

Solving (a): The product

$Product=2*5*7*2*5*7*2*5$

$Product=49000$

Solving (b): The sum of the digits

$Sum = 4 + 9 +0 +0+0$

$Sum = 13$

6 0

3 years ago