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Nat2105 [25]
3 years ago
12

Runner a averages 5 mph and run it B rat averages 6 mph these rates how much longer does it take runner A then runner be to run

15 miles
Mathematics
1 answer:
Kipish [7]3 years ago
8 0
Takes runner A 18 more minutes
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If x – 9 is a factor of x2 – 5x – 36, what is the other factor a. x – 4 b. x 4 c. x – 6 d. x 6
schepotkina [342]
X^2 -5x -36 = x*x -9x+4x -9*4 = x(x-9) +4(x-9) = (x+4)(x-9)

so the second other factor is x+4 so hope that choice wan being x+4 than this will be right just you missed the sign pf plus 

hope this will help you 
5 0
3 years ago
Read 2 more answers
Review the steps of the proof.
lana [24]

Answer:

steps 2 and 3 must be switched

Step-by-step explanation:

e2020

7 0
3 years ago
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A+3 1/4+5 2/9 what is the value of a, explain how you got the answer
larisa86 [58]

Answer:

a+305/36

Step-by-step explanation:

Convert

3

1

4

3

1

4

to an improper fraction.

a

+

13

4

+

5

2

9

a

+

13

4

+

5

2

9

Convert

5

2

9

5

2

9

to an improper fraction.

a

+

13

4

+

47

9

a

+

13

4

+

47

9

To write

13

4

13

4

as a fraction with a common denominator, multiply by

9

9

9

9

.

a

+

13

4

⋅

9

9

+

47

9

a

+

13

4

⋅

9

9

+

47

9

To write

47

9

47

9

as a fraction with a common denominator, multiply by

4

4

4

4

.

a

+

13

4

⋅

9

9

+

47

9

⋅

4

4

a

+

13

4

⋅

9

9

+

47

9

⋅

4

4

Write each expression with a common denominator of

36

36

, by multiplying each by an appropriate factor of

1

1

.

a

+

13

⋅

9

36

+

47

⋅

4

36

a

+

13

⋅

9

36

+

47

⋅

4

36

Combine the numerators over the common denominator.

a

+

13

⋅

9

+

47

⋅

4

36

a

+

13

⋅

9

+

47

⋅

4

36

Simplify the numerator.

a

+

305

36

a

+

305

36

3 0
3 years ago
Read 2 more answers
Write an expression that represents 5 squared.
Korvikt [17]

5 squared is 5^2.

Squared means the power of two, so exponent two.

4 0
3 years ago
There are currently 17 frogs in a (large) pond. The frog population grows exponentially, tripling every 6 days. How long will it
Tema [17]

Answer:

t=11,11 days

Step-by-step explanation:

F=frogs poblation, t=time, be the variables dF/dt = KF, dF/F=Kdt, integrating \int\limits^ {} \, dF/F =K\int\limits^ {} \, dt⇒ LnF=Kt+c,F=ce^{Kt}; Knowing t=0, F=17 and t=6 F=51 (tripling every 6 days (17*3)), F=ce^{K0} = F=c=17; F=17e^{6K} =51⇒e^{6K} =51/17; K6=ln\frac{51}{17} ; K=ln\frac{51}{17}/6=0.183, so F=17e^{0,183t}, now if F=130, t=? we have:

130=17e^{0.183t} =e^{0.183t} =130/17; 0.183t=ln(130/17); t=ln(130/17)/0.183 = 11,11

8 0
3 years ago
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