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nikklg [1K]
4 years ago
5

Which expression represents the greatest common factor (GCF) of 16 and 40? A. 2 x 2 B. 2 x 2 x 3 C. 2 x 2 x 5 D. 2 x 2 x 2

Mathematics
2 answers:
vesna_86 [32]4 years ago
5 0

Answer:

D. 2 x 2 x 2

Step-by-step explanation:

16 is: <u>2 x 2 x 2</u> x 2

40 is: <u>2 x 2 x 2 </u>x 5

16 and 40 have in common are: 2 x 2 x 2  

astraxan [27]4 years ago
4 0

Answer:

D. 2 x 2 x 2

Step-by-step explanation:

I took the quiz, and it was correct. :)

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3 0
3 years ago
Multiply: 4x * root(3, 4x ^ 2) * (2 * root(3, 32x ^ 2) - x * root(3, 2x))
Salsk061 [2.6K]

Answer:

32 {x}^{2} \sqrt[3]{ 2x }    -8{x}^{3}

Step-by-step explanation:

We want to

4x \sqrt[3]{4 {x}^{2} } (2 \sqrt[3]{32 {x}^{2} }  - x \sqrt[3]{2x} )

We expand to obtain:

4x \sqrt[3]{4 {x}^{2} }  \times 2 \sqrt[3]{32 {x}^{2} }  -4x \sqrt[3]{4 {x}^{2} } \times  x \sqrt[3]{2x} )

We now simplify

8x \sqrt[3]{4 {x}^{2}  \times 32 {x}^{2} }    -4 {x}^{2}  \sqrt[3]{4 {x}^{2}  \times 2x}

We multiply the radicand

8x \sqrt[3]{64 \times {x}^{3}  \times 2x }    -4 {x}^{2}  \sqrt[3]{8 {x}^{3}}

Or

8x \sqrt[3]{ {(4x)}^{3}  \times 2x }    -4 {x}^{2}  \sqrt[3]{{(2x)}^{3}}

We take cube root to get:

8x  \times 4x\sqrt[3]{ 2x }    -4 {x}^{2}  \times 2x

We multiply out to get:

32 {x}^{2} \sqrt[3]{ 2x }    -8{x}^{3}

6 0
3 years ago
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