We have the following expression:
(x- (5/2)) ^ 2 = (13/4)
Let's rewrite the given expression:
x ^ 2 - 5x + 25/4 = (13/4)
x ^ 2 - 5x + 25/4 - 13/4 = 0
x ^ 2 - 5x + 12/4 = 0
x ^ 2 - 5x + 3 = 0
Answer:
the original equation given to Sam could have been:
x ^ 2 - 5x + 3 = 0
Answer:
Option A is correct
Step-by-step explanation:
Let the number be z.
Given the statement:
'' five times the quotient of some number and ten"
" quotient of some number and ten" translated to 
"five times the quotient of some number and ten" translated to 
Then, the expression we get,
Therefore, expression represents '' five times the quotient of some number and ten"
Answer:
75,700
Step-by-step explanation:
1. 700. 747 is nearer to 700 and farther from 800.
(1-cos^2(x)) csc^2(x)=1
one of the trigonometry rules is sin^2(x) + cos^2(x) = 1 if you rearrange this you realize that sin^2= 1-cos^2(x)
we also know that csc^2(x)= 1/sin^2(x) so now you can rewrite your equation as:
sin^2(x) x 1/sin^2(x) = 1
sin^2(x)/sin^2(x) =1
the LHS (left hand side) can cancel down to 1 because the numerator and denominator are the same
so then 1=1 Therefore LHS=RHS
Hope this helps
