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Lilit [14]
3 years ago
9

Nellie is buying bird seed to put in her bird feeders. She uses about 10 pounds of bird seed each week, but has room to store an

y extra that she purchases.The bird seed comes in 3 different sizes as given below: 3.5 pounds for $2.52 7.5 pounds for $5.40 11 pounds for $7.92 Nellie is trying to be a smart shopper and get the best deal on the bird seed. Which size bag of bird seed should Nellie buy?
Mathematics
2 answers:
dem82 [27]3 years ago
7 0

Answer:

d is the answer

Step-by-step explanation:

vova2212 [387]3 years ago
3 0
For the answer to the question above, Nellie has to calculate the price per pound for every bag.

1) 2.52 / 3.5 = 0.72 $/lb
2) 5.40/7.5 = 0.72 $/lb
3) 7.92/11 = 0.72 $/lb

Then,  price per pound is the same for any bag. There is no advantage of purchasing one or other, given that she can store any quantity. I hope this helps.
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Given the quadratic function f(x) = (x + 6)(x – 3):
Harlamova29_29 [7]

Answer:

Step-by-step explanation:

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4 0
3 years ago
A couple plans to have children until they get a​ girl, but they agree they will not have more than three​ children, even if all
barxatty [35]

Answer:

a)Let X be number of children

X=1,2,3

P(X=1)= 0.47

P(X=2) = 0.2491

P(X=3) = 0.942923

b) 3.7970

c) 1.6232

Step-by-step explanation:

The complete question is:

A couple plans to have children until they get a​ girl, but they agree they will not have more than three​ children, even if all are boys. Assume that the probability of having a girl is 47.00​%. ​

a) Create a probability model for the number of children​ they'll have.

X=1,2,3

​P(X=1)=??

P(X=2)= ??

P(X=30=???

​(Round to four decimal places as​ needed

​b) Find the expected number of children.

E(X)= ???

​c) Find the expected number of boys​ they'll have.

Expected number of boys= ???

Solution:

Probability of a girl= 0.47

Probability of a boy= 0.53

a) P(X=1)= 0.47

P(X=2) = 0.47× 0.53= 0.2491

P(X=3)= 0.47× 0.53× 0.53 + 0.53× 0.53× 0.53

             = 0.942923

b) E(number of children)= 1× P(X=1) + 2 ×P(X=2) + 3 × (PX=3)

                                       = 3.796969

c) Y: number of boys

P(Y=1)= 0.53×0.47= 0.2491

P(Y=2) = 0.53×0.53×0.47=0.46375

P(Y=3)= 0.53× 0.53× 0.53= 0.148875

E(Y)= P(Y=1)×1 + P(Y=2)×2 + P(Y=3)×3

       = 0.148875×3 +0.46375×2+0.2491 ×1

      = 1.6232

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3 years ago
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