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3 years ago

13

Which number is 100 times greater than 6 thousandths a) 0.6 b)0.06 c)6 d)60

2 answers:

Bumek [7]3 years ago

7 0

6 thousandths = 0.006

0.006 * 100

= 0.6 answer

Alinara [238K]3 years ago

5 0

Your answer would be C.)6. Six thousandths times one hundred is six tenths.

0.006 (six thousandths) X (times) 100(one hundred) = 0.6

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Given that a:b:c= 20 : 35 : 15, a) simplify a : b:c, b) find a:b,

Furkat [3]

Answer:

a) 4:7:3

b) 4:7 / 20:35

c) 3:7 / 15:35

4 0

2 years ago

Sarah is paid biweekly. Her annual salary is $33,000.

bezimeni [28]

Answer:

$1269.23

Step-by-step explanation:

Since Sarah is paid biweekly (every 2 weeks), and there are 52 weeks in a year...

$52$ ÷ $2=26$

Sarah is being paid 26 weeks out of the year.

Divide 33,000 by 26 (I only list 4 places after the decimal):

$33000$ ÷ $26=1269.2307$

Round 1269.2307 to the nearest cent (hundredth):

$1269.23$

3 0

2 years ago

What is the axis of symmetry for f(x) = 2x2 − 4x + 5? (1 point) x = −2 x = −1 x = 1 x = 2

Gnom [1K]

Answer:

y = 2x^2 − 4x + 5

y = 2(x^2 − 2x) + 5

y = 2(x^2 − 2x + 1 - 1) + 5

y = 2(x^2 − 2x + 1) + 5 - 2

y = 2(x - 1)^2 + 3

x = 1 is the axis of symmetry.

Do you agree?

4 0

3 years ago

Read 2 more answers

If the difference of two numbers is even then so is their sum.

Nutka1998 [239]

Answer and explanation:

Statement - If the difference of two numbers is even then so is their sum.

Let the two even numbers be '2m' and '2n' with m and n are integers.

The difference of two number is

$2m-2n=2(m-n)$

Now, The sum of the numbers is

$2m+2n=2(m+n)$

Let $m+n=k$ where k is an integer

Then, $2m+2n=2k$ which is also an even number as 2 is multiplied with it.

So, If the difference of two numbers is even then so is their sum.

For example -

Let two even number 2 and 4.

The difference is $4-2=2$ , 2 is even.

The sum is $4+2=6$ , 6 is even.

4 0

3 years ago

HELP WITH THESE QUESTIONS PART 2... 1 Question

Lunna [17]

<u>Step-by-step explanation</u> and Answers:

$(\frac{1}{\sqrt{10}},\frac{3}{\sqrt{10}})$ is in the format (cos, sin). So, adjacent = 1, opposite = 3, hypotenuse = $\sqrt{10}$

sin = $\frac{opposite}{hypotenuse}$ = $\frac{3}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}})$ = $\frac{3\sqrt{10}}{10}$

cos = $\frac{adjacent}{hypotenuse}$ = $\frac{1}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}})$ = $\frac{\sqrt{10}}{10}$

tan = $\frac{opposite}{adjacent}$ = $\frac{3}{1}$ = 3

csc = $\frac{hypotenuse}{opposite}$ = $\frac{\sqrt{10}}{3}$

sec = $\frac{hypotenuse}{adjacent}$ = $\frac{\sqrt{10}}{1}$ = $\sqrt{10}$

cot = $\frac{adjacent}{opposite}$ = $\frac{1}{3}$

7 0

3 years ago