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3 years ago

What is the area of this parallelogram?

Mathematics

2 answers:

denis-greek [22]3 years ago

5 0

Answer:

Step-by-step explanation:

A = b x h

denpristay [2]3 years ago

4 0

The answer is 45....................

yeeeeeeeeeeeeeeet ..............

:)

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The scale of a room in a blueprint is 3in:5ft. A wall in the same blueprint is 18in. Plzzz complete table

postnew [5]

we know that

[scale]=[blueprint]/[actual]-------> [actual]=[blueprint]/[scale]

[scale]=3/5 in/ft

for [wall blueprint]=18 in

[wall actual]=[wall blueprint]/[scale]-------> 18/(3/5)----> 30 ft

Part A)

the actual wall is 30 ft long

Part B) window has actual width of 2.5 ft

[ window blueprint]=[scale]*[actual window]-----> (3/5)*2.5----> 1.5 in

the width of the window in the blueprint is 1.5 in

Part C) Complete the table

For [blueprint length]=4 in

[actual length]=[blueprint length]/[scale]-------> 4/(3/5)----> 20/3 ft

For [blueprint length]=5 in

[actual length]=[blueprint length]/[scale]-------> 5/(3/5)----> 25/3 ft

For [blueprint length]=6 in

[actual length]=[blueprint length]/[scale]-------> 6/(3/5)----> 30/3=10 ft

For [blueprint length]=7 in

[actual length]=[blueprint length]/[scale]-------> 7/(3/5)----> 35/3 ft

For [actual length]=6 ft

[blueprint length]=[actual length]*[scale]-------> 6*(3/5)----> 18/5 in

For [actual length]=7 ft

[blueprint length]=[actual length]*[scale]-------> 7*(3/5)----> 21/5 in

For [actual length]=8 ft

[blueprint length]=[actual length]*[scale]-------> 8*(3/5)----> 24/5 in

For [actual length]=9 ft

[blueprint length]=[actual length]*[scale]-------> 9*(3/5)----> 27/5 in

6 0

3 years ago

Please help! ( WIll mark Brianliest ) <br><br> Help

sashaice [31]

Answer:y= (3/4)x -7/4

Step-by-step explanation:

[y -(-1)]/[x - 1] = [2 -(-1)]/[5 - 1]

[y + 1]/[x - 1] = 3/4

y + 1 = (3/4)x - 3/4

y = (3/4)x - 7/4.

6 0

3 years ago

Please help I’ll make you brainliest

asambeis [7]

Answer:

Step-by-step explanation: 3. 12240 watts

4. 101.82 pounds of insecticide.

6 0

3 years ago

Given an initial quantity Q0=150 and a growth rate of 7% per unit time, give a formula for the quantity Q as a function of time

rodikova [14]

Answer:

Step-by-step explanation:

From the given information:

(a)

Since growth quantity is not continuous

$Q(t) = 150 (1.07)^t$

For t = 10

$Q(10) = 150 (1.07)^{10}$

$\mathbf{Q(10) = 295.073}$

(b)

Here, for a continuous growth rate, the growth quantity can be computed in terms of initial quantity and the growth rate.

i.e.

$Q(t) = 150 e^{0.07t}$

At t = 10 for a continuous growth rate;

$Q(10) = 150 e^{0.07 \times 10}$

$Q(10) = 150 e^{0.7}$

$\mathbf{Q(10) = 302.063}$

8 0

3 years ago

In the coordinate plane, the point A, 4− 2 is translated to the point A′, 1− 5. Under the same translation, the points B, 7− 4 a

Inga [223]

Answer:

The coordinates of B' and C' are $B'(x,y) = (4, -7)$ and $C'(x,y) = (-1, -8)$ , respectively.

Step-by-step explanation:

From the Linear Algebra, we define the translation of a given point as:

$O'(x,y) = O(x,y) + T(x,y)$ (1)

Where:

$O(x,y)$ - Original point, dimensionless.

$T(x,y)$ - Translation vector, dimensionless.

$O'(x,y)$ - Translated point, dimensionless.

If we know that $A'(x,y) = (1, -5)$ and $A(x,y) = (4,-2)$ , then the translation vector is:

$T(x,y) = A'(x,y)-A(x,y)$ (2)

$T(x,y) = (1,-5)-(4,-2)$

$T(x,y) = (-3,-3)$

If we know that $B(x,y) = (7,-4)$ , $C(x,y) = (2,-5)$ and $T(x,y) = (-3,-3)$ , then the translated points are, respectively:

$B'(x,y) = B(x,y)+T(x,y)$ (3)

$B'(x,y) = (7,-4) +(-3,-3)$

$B'(x,y) = (4, -7)$

$C'(x,y) = C(x,y) +T(x,y)$

$C'(x,y) = (2,-5) + (-3,-3)$

$C'(x,y) = (-1, -8)$

The coordinates of B' and C' are $B'(x,y) = (4, -7)$ and $C'(x,y) = (-1, -8)$ , respectively.

5 0

2 years ago