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Elan Coil [88]
3 years ago
14

Y divided by 9 equals 81

Mathematics
2 answers:
algol [13]3 years ago
5 0
If you do 81 x 9 which equals 729. If you want to check, you do 729 divided by 9 and you get 81.
Luba_88 [7]3 years ago
5 0

Answer:

729

Step-by-step explanation:

In order to solve this, you need to do the reverse operation. The question is about division, so that means we are going to do multiplication. If we multiply 9x81, we will know what divided by 9 equals 81.

9x81=729

So 729 divided by 9 equals 81.

To check this just plug the number you got back into the orignal equation:

Y divided by 9 equals 81

729 divided by 9 equals 81

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What’s is the surface area of this
Marysya12 [62]
2.8 multiplied by 2.8 to find the surface area of the base which is 7.84
4*1/2*2.8*5.5 to find the surface area of all four triangular faces which is 30.8
Plus them together 7.84 plus 30.8 which is 38.64
6 0
3 years ago
Which equation represents a function of x that is not linear?
AnnyKZ [126]

Answer:

y = 4x+3x^2

Step-by-step explanation:

For an equation to be linear, x must have a power of 1

y = 4x+3x^2 has a power of x that is not x  ( x^2) so this is not linear  ( it is quadratic)

8 0
3 years ago
The bad debt ratio for a financial institution is defined to be the dollar values of loans defaulted divided by the total dollar
Nimfa-mama [501]

Answer:

(a) NULL HYPOTHESIS, H_0 : \mu \leq  3.5%

    ALTERNATE HYPOTHESIS, H_1 : \mu > 3.5%

(b) We conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Step-by-step explanation:

We are given that a random sample of seven Ohio banks is selected.The bad debt ratios for these banks are 7, 4, 6, 7, 5, 4, and 9%.The mean bad debt ratio for all federally insured banks is 3.5%.

We have to test the claim of Federal banking officials that the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

(a) Let, NULL HYPOTHESIS, H_0 : \mu \leq  3.5% {means that the the mean bad debt ratio for Ohio banks is less than or equal to the mean for all federally insured banks}

ALTERNATE HYPOTHESIS, H_1 : \mu > 3.5% {means that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks}

The test statistics that will be used here is One-sample t-test;

                T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where,  \bar X = sample mean debt ratio of Ohio banks = 6%

             s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} } = 1.83%

             n = sample of banks = 7

So, test statistics = \frac{6-3.5}{\frac{1.83}{\sqrt{7} } }  ~ t_6

                             = 3.614

(b) Now, at 1% significance level t table gives critical value of 3.143. Since our test statistics is more than the critical value of t so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Hence, Federal banking officials claim was correct.

7 0
3 years ago
Can anyone help with this question?.. thanks in advance!!
agasfer [191]
Hell naw, nobody is about to do that for you
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What is p(less than 2)​
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i think it would be 2<p

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