What is the net force on this object? Small box with dot in the middle. Arrows originate at dot. Arrow up and Arrow down are sam
e length. Arrow up labeled F sub norm equals 20 N and Arrow down labeled F sub grav equals 20 N. Arrow to the right is longer than arrow to the left. Arrow to the right is labeled F sub app equals 22 N and arrow to the left is labeled F sub frict equals 14 N. 0 newtons 8 newtons 22 newtons 36 newtons
2 answers:
Answer:
The net force is 8N.
Step-by-step explanation:
Consider the provided information.
Two forces cancel each other if they are in opposite direction and the forces are equal, the net force is zero in this case.
Now consider the figure 1:
Here, vertical forces (up and down) cancel each other and horizontal forces do not cancel each other, thus the force is unbalanced.
Calculate the net force as shown:
Substitute in above formula.
Hence, the net force is 8N.
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First, write the equation of the line containing the points <span>(2,-5) and (-3,2).
We can use 2 point form, or point-slope form.
Let's use </span>point-slope form.
the slope m is
, then use any of the points to write the equation. (ex, pick (2, -5))
y-(-5)=(-7/5)(x-2)
y+5=(-7/5)x+14/5
y= (-7/5)x+14/5 - 5 =(-7/5)x+14/5 - 25/5 =(-7/5)x-11/5
Thus, the lines are
i) y=-ax+4 and ii) y=(-7/5)x-11/5
the slopes are the coefficients of x: -a and (-7/5),
the product of the slopes of 2 perpendicular lines is -1,
so
(-a)(-7/5)=-1
7/5a=-1
a=-1/(7/5)=-5/7
Answer: -5/7
We can use 2 point form, or point-slope form.
Let's use </span>point-slope form.
the slope m is
y-(-5)=(-7/5)(x-2)
y+5=(-7/5)x+14/5
y= (-7/5)x+14/5 - 5 =(-7/5)x+14/5 - 25/5 =(-7/5)x-11/5
Thus, the lines are
i) y=-ax+4 and ii) y=(-7/5)x-11/5
the slopes are the coefficients of x: -a and (-7/5),
the product of the slopes of 2 perpendicular lines is -1,
so
(-a)(-7/5)=-1
7/5a=-1
a=-1/(7/5)=-5/7
Answer: -5/7