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nika2105 [10]
3 years ago
8

A flight attendant surveyed passengers on a flight about where they wouldprefer to sit. The results are shown in the table Aisle

Window Total 8 12 Back 10 14 24 Front 4 Total 14 22 36 What is the probability that a passenger prefers to sit in the front of the plane and prefersS a window seat? ​
Mathematics
2 answers:
slava [35]3 years ago
6 0

Answer:

c. 4/11 I think

Step-by-step explanation:

Elodia [21]3 years ago
3 0

Answer:

Step-by-step explanation:

26

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Helppp pleaseeee!!!!!!!!!!!
kvv77 [185]

Step-by-step explanation:

i can't see ur question the pic is black can u resend

6 0
3 years ago
Read 2 more answers
Find the length of each segment. SEE EXAMPLES 1 AND 2
wlad13 [49]

The lengths of the line segments are summarized in the following list:

  1. DF = 3
  2. DE = 8 / 3
  3. FG = 3
  4. FH = 9 / 2
  5. GH = 3 / 2
  6. EH = - 11 / 6
<h3>How to calculate the length of a line segment based on point set on a number line</h3>

Herein we have a number line with five points whose locations are known.  The length of each line segment is equal to the arithmetical difference of the coordinates of the rightmost point and the leftmost point:

DF = - 1 - (- 4)

DF = 3

DE = (- 1 - 1 / 3) - (- 4)

DE = 3 - 1 / 3

DE = 8 / 3

FG = 2 - (- 1)

FG = 3

FH = (3 + 1 / 2) - (- 1)

FH = 4 + 1 / 2

FH = 9 / 2

GH = (3 + 1 / 2) - 2

GH = 1 + 1 / 2

GH = 3 / 2

EH = (3 + 1 / 2) + (- 1 - 1 / 3)

EH = - 2 + (1 / 2 - 1 / 3)

EH = - 2 + 1 / 6

EH = - 11 / 6

To learn more on lengths: brainly.com/question/8552546

#SPJ1

7 0
2 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
In the following. Diagram line is parallel to line be find the measure of angle X
Mrac [35]
Isjwkddjkwhdjxjwkhsidhwjhaosjshwuwjw
7 0
3 years ago
Solve 20x + 5y= for y
Mama L [17]

Answer:

<h2>y = -4x</h2>

Step-by-step explanation:

Solve 20x + 5y =  for y

20x + 5y = 0

subtract 20x both sides

5y = -20x

simplify:

y = <u>-20x</u>

        5

finally

y = -4x

3 0
3 years ago
Read 2 more answers
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