The answer for S will be 49/4.
Janet can fill a certain order in 5 hours, therefore she performs 1/5 of the order within 1 hour.
Tom needs 8 hours to do the same job, therefore he performs 1/8 of the order within 1 hour.
Working together, they make 1/5 + 1/8 orders within 1 hour.
Let <em>t</em> mean the number of hours they need. Then we have equation:
Given:
Consider the given equation is
To find:
The missing value in the given equation and complete the equation.
Solution:
We have,
Taking LHS, we get
and,
Let the missing value be k.
For each equation LHS=RHS.
Therefore, the missing value is 10 and the complete equation is .
This is a mixture problem.
Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.
mass1 * karat1 + mass2*karat = total mass * total carat
Let mass1 be x g. mass 2 would be = (200 -x)
karat 1 = 9 karat 2 = 18
Total mass = 200g.
Total karat = 14.
9*x + 18*(200 -x) = 14*200
9x + 18*200 - 18*x = 14*200
18*200 + 9x - 18x = 14*200
3600 - 9x = 2800
3600 - 2800 = 9x
800 = 9x
9x = 800
x = 800/9
x ≈ 88.89
Therefore 88.89 grams of 9 karat gold must be mixed.