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jok3333 [9.3K]
3 years ago
13

Alex surveyed his classmates to determine who has been surfing and who has been snowboarding. Let A be the event that a classmat

e HAS snowboarded and let B be the event that a classmate HAS surfed.
If Alex picked a classmate at random, what is P(B/A) ?

A. 4/21
B. 3/4
C. 4/25
D. 25/28

Mathematics
2 answers:
DIA [1.3K]3 years ago
5 0

Answer:

surburu

Step-by-step explanation:

stealth61 [152]3 years ago
5 0

Answer:

B. \frac{3}{4}

Step-by-step explanation:

<u>I got this question correct. :)</u>

  • A: Snowboarded
  • B: Surfed
<h3>P(B|A) = P(A and B) / P(A)</h3>

P(Surfed|Snowboarded) = P(Surfed and Snowboarded) / P(Snowboarded)

  • Amount surfed and snowboarded: 36
  • Total amount snowboarded: 48

P(B|A) = \frac{36}{48} = \frac{3}{4}

Apologies for lack of explanation, but I think this will do it.

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