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3 years ago

How to find the vertex of a parabola given a quadratic equation?

Mathematics

1 answer:

Nat2105 [25]3 years ago

8 0

$let \: f(x) = ax {}^{2} + bx + c \\ thus \: f(x) \: represents \: a \: parabola \: whose \: axis \: is \: parallel \: to \: the \: y \: axis \: and \: vertex \: is \: \frac{ - b}{2a} ,\frac{ - d}{4a} \\$

At the respective max and min values

You might be interested in

Write a recursive formula for an, the nth term of the sequence 3, -4, -11

yKpoI14uk [10]

Answer:

, 12, 48, 192...

a. Write a recursive formula for the nth term of the sequence

Ans: a(n+1) = 4*a(n)

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b. Write a general formula for the nth term of the sequence

a(n) = 3*4^(n-1)

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c. Calculate S10 for this sequence

Geometric sequence with a(1) = 3 and r = 4

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Step-by-step explanation:

8 0

3 years ago

There are 7 stars in each course on Mario 64. What percentage of stars

Elina [12.6K]

2 divided by 7 would give you 29%

7 0

3 years ago

In spherical geometry, all points are points on the surface of a sphere. A line is a circle on the sphere whose diameter is equa

mamaluj [8]

Answer: It is not possible that two triangles that are similar and not congruent in spherical geometry.

Step-by-step explanation:

For instance, taking a circle on the sphere whose diameter is equal to the diameter of the sphere and inside is an equilateral triangle, because the sphere is perfect, if we draw a circle (longitudinal or latitudinal lines) to form a circle encompassing an equally shaped triangle at different points of the sphere will definately yield equal size.

in other words, triangles formed in a sphere must be congruent and also similar meaning having the same shape and must definately have the same size.

Therefore, it is not possible for two triangles in a sphere that are similar but not congruent.

Two triangles in sphere that are similar must be congruent.

8 0

3 years ago

The diameter of cold virus cell is about 3x10-9 meter,and the diameter of a streptoccus bacterium cell is about 9x10-7 meter. Wh

Archy [21]

Here we need to compare the orders of magnitude of two measures.

We will see that the bacteria is 300 times larger than the virus.

We know that:

The diameter of the virus-cell is:

$D_v = 3 \cdot 10^{-9} m$

The diameter of the bacteria cell is:

$D_b = 9 \cdot 10^{-7} m$

So, to compare them, first notice that both are in the same units, meters, so we only need to compare the numbers.

Is common sense to identify the one with the largest exponent as the largest number, and the largest exponent is -7, thus the bacteria should be the larger one.

But let's prove this with math, remember the property:

$\frac{a^n}{a^m} = a^{n - m}$

Let's take the quotient between the diameters and see what we get, I will use the diameter of the bacteria in the numerator, thus if the quotient is larger than 1, it would mean that the bacteria is greater and by how much.

$quotient = \frac{ 9 \cdot 10^{-7} m}{ 3 \cdot 10^{-9} m} = \frac{9}{3} \cdot 10^{-7 + 9}\\\\= 3*10^2$

So we can say that the bacteria is 3*10^2 = 3*100 = 300 times larger than the virus.

If you want to learn more, you can read:

brainly.com/question/4953281

8 0

2 years ago

How do you solve -5m+9n= 15, for m

Fed [463]

Answer:

m= 9/5 n - 3

Step-by-step explanation:

Let's solve for m.

−5m+9n=15

Step 1: Add -9n to both sides.

−5m+9n+−9n=15+−9n

−5m=−9n+15

Step 2: Divide both sides by -5.

-5m/-5 = -9n+15/-5

m= 9/5 n - 3

4 0

3 years ago