Identify two tables which represent quadratic relationships

Mathematics

2 answers:

lord [1]3 years ago

3 0

Answer:

Tables 3 and 5

Step-by-step explanation:

if you know that quadratic equations from curves, then, check out the number patterns on 3 and 5, then, compare them with the others, you'll see

maksim [4K]3 years ago

3 0

Answer:

Table 3 and 4

Step-by-step explanation:

Let us understand the coordinates symmetry of the graphs of quadratic equations.

In a quadratic equation, we have a polynomial in x with degree 2. Hence the result in y or P(x) do get repeated as polynomial contains $x^2$ in it.

Thus by analysing the tables we see that in table 3 , y= -10 gets repeated and in table 4 , y =4 and y=-4 repeated. Hence they are the graph of a quadratic polynomial

You might be interested in

What is the 50th term of the sequence that begins -4, 2, 8, 14....?

vagabundo [1.1K]

Answer:

$a_{50}=290$

Step-by-step explanation:

Notice that we are in the presence of an arithmetic sequence (there is a common difference of 6 between a term and the next). So thisis an arithmetic sequence with first term $a_1=-4$ . and common difference "<em>d</em>" = 6.

Recall now the formula for the nth term ( $a_n$ ) of an arithmetic sequence:

$a_n=a_1+(n-1)\,d$

Then, using our values in the formula, we get:

$a_n=a_1+(n-1)\,d\\a_{50}=-4+(50-1)\,6\\a_{50}=-4+(49)\,6\\a_{50}=290$

7 0

3 years ago

Answer with the explanation step by step

andrey2020 [161]

Answer:

The answer is A. $\frac{3(x-21)}{(x+7)(x-7)}$ .

Step-by-step explanation:

To find the difference of this problem, start by simplifying the denominator, which will look like $\frac{3}{x+7}-\frac{42}{(x+7)(x-7)}$ . Next, multiply $\frac{3}{x+7}$ by $\frac{x-7}{x-7}$ to create a fraction with a common denominator in order to subtract from $\frac{42}{(x+7)(x-7)}$ . The problem will now look like $\frac{3}{x+7}*\frac{x-7}{x-7}-\frac{42}{(x+7)(x-7)}$ .

Then, simplify the terms in the problem by first multiplying $\frac{3}{x+7}$ and $\frac{x-7}{x-7}$ , which will look like $\frac{3(x-7)}{(x+7)(x-7)}-\frac{42}{(x+7)(x-7)}$ . The next step is to combine the numerators over the common denominator, which will look like $\frac{3(x-7)-42}{(x+7)(x-7)}$ .

Next, simplify the numerator, and to simplify the numerator start by factoring 3 out of $3(x-7)-42$ , which will look like $\frac{3(x-7-14)}{(x+7)(x-7)}$ . Then, subtract 14 from -7, which will look like $\frac{3(x-21)}{(x+7)(x-7)}$ . The final answer will be $\frac{3(x-21)}{(x+7)(x-7)}$ .