All categories

2 years ago

What is 5/10 + 8/100

Mathematics

1 answer:

Greeley [361]2 years ago

7 0

Answer:

$\frac{29}{50}$

Step-by-step explanation:

We have two fractions and are being asked to add them both.

5/10 and 8/100 don't have the fractions, but 5/10 can be simplified to 1/2, meaning that to make the same denominator, we have to find the half of 100, which would be 50. Now turn the fraction into 50/100.

50/100 + 8/100

58/100

This can be simplifed :

$\frac{58/2}{100/2}$

$\frac{29}{50}$

You might be interested in

Kersha has two jobs. During the day she works as an office clerk, and in the evening she works as a cashier. Her office job pays

aliya0001 [1]

Use a number line to help, or a tape diagram.

5 0

3 years ago

Which is a name for the angle shown? Select two answers

alexandr402 [8]

Answer:

I'm not sure how to answer is but i think its called < CDE or < EDC or it is an acute angle.

Step-by-step explanation:

7 0

3 years ago

What is the area of the circle whose equation is (x − 9)2 + (y − 3)2 = 64?

aalyn [17]

(x-xo)²+(y-yo)²=r²
(x-9)²+(y-3)²=64
r²=64
Area of a circle=πr²=3.14×64=200.96

7 0

3 years ago

Use series to verify that<br><br> <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{

SVETLANKA909090 [29]

$y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\$

$\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\$

This shows that $y' = y$ is true when $y = e^x$

-----------------------

Note 1: A more general solution is $y = Ce^x$ for some constant C.
Note 2: It might be tempting to say the general solution is $y = e^x+C$ , but that is not the case because $y = e^x+C \to y' = e^x+0 = e^x$ and we can see that $y' = y$ would only be true for C = 0, so that is why $y = e^x+C$ does not work.

6 0

3 years ago

3x-4y=-5 y=4x-2 Is (1,2) a solution of the system?

Orlov [11]

If you want to check if (1,2) is a solution to the system, you have to plug the x and y values back into both equations. If they work for one equation, but not the other, than the coordinates are not a solution to the system.

3(1) - 4(2) = -5
3 - 8 = -5
-5 = -5

2 = 4(1) - 2
2 = 4 - 2
2 = 2

Since both of these checks are true, then (1,2) is a solution to the system.

7 0

3 years ago