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3 years ago

Which statement is true about the given function

Mathematics

2 answers:

galina1969 [7]3 years ago

5 0

This is the answer

f(x) < 0 over the intervals (–, –2.7) and (–1, 0.8).

madam [21]3 years ago

3 0

The y-intercept is -2

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Jason states that -5.0 is not an integer because it is a decimal. Is he correct? Why or why not?

gulaghasi [49]

Answer:

The answer is No, he's incorrect

Step-by-step explanation:

Because -5.0 is still -5 so therefore it makes -5.0 an integer

5 0

3 years ago

Write an equation of the line perpendicular to the line 8x+15y=12 and containing the point (11,17) write the answer in standard

jek_recluse [69]

The slope of a line perpendicular to another line has a slope which is the negative reciprocal of that line or:

m1 = -1/m2

First, we convert the given equation into slope-intercept form of a line: y = mx + b

8x + 15y = 12

15y = -8x + 12

y = (-8/15) x + 0.8

m1 = -8 / 15

Therefore the slope of the perpendicular line is:

m2 = 15 / 8

Since the perpendicular line crosses the point (11, 17), therefore using the slope formula:

m = (y2 – y1) / (x2 – x1)

15 / 8 = (y2 – 17) / (x2 – 11)

1.875 (x2 – 11) = y2 – 17

1.875 x2 – 20.625 = y2 – 17

y2 = 1.875 x2 – 3.625

y = (15/8) x – 3.625

multiplying both sides by 8:

8y = 15x – 29

rewriting in standard form:

<span>15x – 8y = 29 (ANSWER)</span>

3 0

3 years ago

Which relationship describes angles 1 and 2? Select each correct answer. A adjacent angles B complementary angles C vertical ang

Scrat [10]

The correct answer for this question is this one:
<span>- A adjacent angles
-D supplementary angles

The relationship that describes angle 1 and angle 2 is that they are adjacent angles -- at the same time they are also supplementary angles.</span>
Hope this helps answer your question and have a nice day ahead.

3 0

3 years ago

Read 2 more answers

Decrease 18•4 in the ratio 3:8

andrezito [222]

Answer:

6.9

Step-by-step explanation:

Since you are supposed to decrease the number in the ratio 3:8 or 3/8 you take the small number that is 3 to be the numerator and 8 to be the denominator then multiply it by 18.4.

That is 18.4×3:8= 184/10×3/8=6.9

So to decrease a number you multiply it with the smallest number as the numerator and the big number as the denominator

To increase a number you multiply it with the big number as the numerator and the small number to be the denominator

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8 0

3 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

zheka24 [161]

<h2>Hello!</h2>

The answer is:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$

Then, since we know that they covered a combined distance which is equal to 264 miles of distance in 2 hours + 45 minutes, we have:

$2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours$

Writing the equation, we have:

$264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph$

We have that the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

$SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph$

Hence, we have that:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

4 0

3 years ago

Read 2 more answers