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mel-nik [20]
3 years ago
7

Can someone please help me with these questions ?!!!

Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

Step-by-step explanation:

1.) 7,24,25

2.) 1,2,3

This is all I can help with the rest is blurry.

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Peter left city a at 9:00 am towards city b at an average speed of 50 mph. Thirty minutes later Emily also leaves city a towards
Archy [21]

Answer:

62.5 mph

Step-by-step explanation:

Given that :

Peter :

Speed = 50mph

Start Time = 9 a. M

Emily :

Start time = 9:30

Speed = x

In other to catch up at 11:30 :

Peter (11:30 - 9:00) = 2hours 30 minutes = 2.5 hrs

Total distance moved by Peter :

Speed * time = 50 * 2.5 = 125miles

For Emily to cover 125 miles in (11:30 - 9:30) = 2 hours

Speed = distance / time

Speed = 125 miles / 2 hours

Speed = 62.5 miles per hour

7 0
3 years ago
What is the product of (3a + 2)(4a2 - 2a + 9)?
natka813 [3]

Answer:

12a³+2a²+23a+18

Step-by-step explanation:

(3a+2)(4a²-2a+9)=

12a³-6a²+27a+8a²-4a+18=

12a³+2a²+23a+18

If you need more explanation, reply to this answer.

4 0
4 years ago
Whoever can answer this I would really appreciate it
Trava [24]

Slope = change in y / change in x


Use the two pints shown on the graph.


Slope = ( 0- -2) / ( -6 -2)

Slope = 2/-8

Slope = -1/4


answer: slope = -1/4

4 0
2 years ago
Read 2 more answers
A B R and P are four points on a circle with centre 0. A O R and C are four points on a different circle. The two circles inters
Slav-nsk [51]

Answer:

x° = ∠OBR = ∠ABC (base angles of a cyclic isosceles trapezoid)

Step-by-step explanation:

APRB form a cyclic trapezoid

∠APO  = x° (Base angle of an isosceles triangle)

∠OPR  = ∠ORP (Base angle of an isosceles triangle)

∠ORB = ∠OBR (Base angle of an isosceles triangle)

∠APO + ∠OPR + ∠OBR = 180° (Sum of opposite angles in a cyclic quadrilateral)

Similarly;

∠ORB + ∠ORP + x°  = 180°

Since ∠APO = x° ∠ORB = ∠OBR and ∠OPR  = ∠ORP we put

We also have;

∠OPR = ∠AOP = ∠BOR (Alternate interior angles of parallel lines)

Hence 2·x° + ∠AOP = 180° (Sum of angles in a triangle) = 2·∠OBR + ∠BOR

Therefore, 2·x° = 2·∠OBR, x° = ∠OBR = ∠ABC.

6 0
3 years ago
How do you represent any number in an equation?
RideAnS [48]
Any unknown number in an equation you represent with a variable
5 0
3 years ago
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