The domain is (-∞,∞)
the range is (−∞,2]
9 would be the first number and 7 would be the second.
7 1/4
that is the numerical difference between the two
The 3.1 °F/min rate of change of the temperature and 15 minutes change duration gives the change in temperature as 46.5 °F
<h3>How can the change in temperature be found from the rate of change?</h3>
The rate at which the temperature changed = 3.1 °F/min
The duration of the change in temperature = 15 minutes
The relationship between the change in temperature, the rate of change in temperature and the time can be presented as follows;
![3.1 ^{\circ} F/min = \frac{ \delta T }{\delta t} = \frac{ \Delta T }{ \Delta t}](https://tex.z-dn.net/?f=3.1%20%20%5E%7B%5Ccirc%7D%20F%2Fmin%20%3D%20%20%5Cfrac%7B%20%5Cdelta%20T%20%7D%7B%5Cdelta%20t%7D%20%20%3D%20%20%5Cfrac%7B%20%5CDelta%20T%20%7D%7B%20%5CDelta%20t%7D)
Where;
∆T = The required change in temperature
∆t = The duration of the change = 15 minutes
Which gives;
∆T = 3.1°F/min × 15 minutes = 46.5 °F
- The change in temperature, ∆T = 46.5 °F
Learn more about the rate of change of a variable here:
brainly.com/question/10208814
#SPJ1
We can easily get the quarts per hour rate by dividing the number of quarts by the number of hours:
![\text{29 quarts in 5 hours} \implies \dfrac{29}{5} = 5.8 \text{ quarts in 1 hour}](https://tex.z-dn.net/?f=%5Ctext%7B29%20quarts%20in%205%20hours%7D%20%5Cimplies%20%5Cdfrac%7B29%7D%7B5%7D%20%3D%205.8%20%5Ctext%7B%20quarts%20in%201%20hour%7D)
Now that we have the quarts per hour rate, we can easily address the question: the factory could make
![5.8\cdot 48 = 278.4](https://tex.z-dn.net/?f=5.8%5Ccdot%2048%20%3D%20278.4)
quarts in 48 hours, with a daily rate of
![5.8\cdot 24 = 139.2](https://tex.z-dn.net/?f=5.8%5Ccdot%2024%20%3D%20139.2)
quarts per day