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3 years ago

Find the volume using the formula V= πr2h

Mathematics

1 answer:

Dimas [21]3 years ago

7 0

Answer: $V=254.46\ in^3$

Step-by-step explanation:

The formula for calculate the volume of a cylinder is the one given in the exercise:

$V=\pi r^2h$

Where "r" is the radius and "h" is the height of the cylinder.

You need to observe the figure given in the exercise. You can notice that the radius and the height of that cylinder are the following:

$r=3\ in\\\\h=9\ in$

Then, knowing those values, you can substitute them into the formula:

$V=\pi (3\ in)^2(9\ in)$

Finally you must evaluate in order to find the volume of the cylinder. You get the following result:

$V=\pi (9\ in^2)(9\ in)\\\\V=81\pi\ in^3\\\\V=254.46\ in^3$

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3 years ago

Given a right triangle find the measure of all the angles of one angle is a right angle in the measure of the second angle is si

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Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
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center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

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