6th grade math, help me please.
1 answer:
You might be interested in
Answer:
y = -(1/12)(x -6)² -2
Step-by-step explanation:
The vertex of the parabola is halfway between the focus and the directrix, so has y-coordinate (-5+1)/2 = -2. The difference in the y-coordinates between the focus and the vertex is ...
p = -5 -(-2) = -3
An equation of the parabola with vertex (h, k) and focus-vertex distance p can be written:
y = 1/(4p)(x -h)² +k
For (h, k) = (6, -2) and p = -3, the equation is ...
y = (-1/12)(x -6)² -2
Notice the picture
the semicircle, has a radius of "r", you can use that to get the area of a circle, then half it, that's the area of that semicircle in "r" terms,
now, look at the rectangle the semicircle is sitting on top of, to make up
the normal window, it has a height of 3r, and notice its width
so, get the area of the semicircle, and the area of the rectangle,
both in r-terms
add them up, and that's the area of the window
the semicircle, has a radius of "r", you can use that to get the area of a circle, then half it, that's the area of that semicircle in "r" terms,
now, look at the rectangle the semicircle is sitting on top of, to make up
the normal window, it has a height of 3r, and notice its width
so, get the area of the semicircle, and the area of the rectangle,
both in r-terms
add them up, and that's the area of the window