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Mkey [24]
3 years ago
7

The length of a rectangle is twice it’s width. If the area of the rectangle is 162m ^2,find its perimeter

Mathematics
2 answers:
irga5000 [103]3 years ago
7 0

Answer:

54 m

Step-by-step explanation:

First, find the width

 162 = 2w × w

 162 = 2w²

 w² = 162 ÷ 2

 w = \sqrt{81}

 w = 9 m

┈

Second, find the length

 l = w × 2

 l = 9 × 2

 l = 18 m

┈

Then, find the perimeter

 perimeter = 2(l + w)

 perimeter = 2(18 + 9)

 perimeter = 2(27)

 perimeter = 54 m

GalinKa [24]3 years ago
6 0

Answer:

{ \tt{area = length \times width}} \\ { \tt{162 = 2w \times w}} \\ { \tt{162 = 2 {w}^{2} }} \\ { \tt{ {w}^{2}  = 81}} \\ { \tt{w = 9}}

  • width, w = 9 m
  • length, l = 2 × 9 = 18 m

{ \tt{perimeter = 2(l + w)}} \\ { \tt{p = 2(18 + 9)}} \\ { \tt{p = 2 \times 27}} \\  \\ { \underline{ \tt{ \:  \: perimeter = 54 \: m \:  \: }}}

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