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3 years ago

Someone please help...due todayyy

Mathematics

1 answer:

IRISSAK [1]3 years ago

4 0

Answer: I believe it is 1.1x10^-8

Step-by-step explanation:

Because 3.4x10^2 divided by 3x10^10 gives you 0.00000011 which is then converted through scientific notation into 1.1 x10^-8

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Jake bought 14.5 pounds of dried navy beans for $25.52.

dsp73

Answer:40.00

Step-by-step explanation:just add

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3 years ago

Can someone help me please

nadya68 [22]

To calculate mean you add up all the numbers you have, then divide it by the total pieces of data, for example: 2 4 3 1 = 2+4+3+1=10 10÷4=2.5

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Comment if you want the answers.

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3 years ago

Please help me I will give you the brain thing with extra points if you help me, please. I need to get this right. 5/5

sveta [45]

C, reflection over the x axis

5 0

3 years ago

Read 2 more answers

How do I use the arc length to find the circumference ?

Mashutka [201]

arc length = circumference • [central angle (degrees) ÷ 360]

Solving this equation for circumference:

circumference = arc length / (central angle / 360)

circumference = 12 / (85/360)

circumference = 12 / 0.2361111111 

circumference = 50.8235294118 

Source:
http://www.1728.org/radians.htm

8 0

3 years ago

Consider the function f(x)=x2e4x. f(x) has two inflection points at x = C and x = D with C≤D where C is and D is Finally for eac

fredd [130]

Answer:

the inflection points are

$x = -0.85, -0.14$

So,

$C = -0.85 \\D = -0.14$

It is concave down at the intervals

$(-\infty , -0.85] \cup [-0.14,\infty)$

And it would be concave up at

$(-0.85 , -0.14)$

Step-by-step explanation:

Remember that to find inflection points you need to find where

$f''(x) = 0$

Since

$f(x) = x^2 e^{4x}$

Then using the product and the chain rule you have that

$f'(x) = 2e^{4x} x(2x+1)$

And then, using again the chain rule and the product rule you have that

$f''(x) = 2e^{4x} (8x^2 +8x+1)$

Therefore you have to solve the equation

$8x^2 +8x+1 = 0$

Using the quadratic equation you get that there are two solutions, so the inflection points are

$x = -0.85, -0.14$

So,

$C = -0.85 \\D = -0.14$

Now remember that a function is concave up if the derivative is greater than zero and concave down if the derivative is less than zero. Therefor you have to solve these inequalties

$8x^2 +8x+1 < 0 \\8x^2 +8x+1 \geq 0$

And you would get that is concave down at the intervals

$(-\infty , -0.85] \cup [-0.14,\infty)$

And it would be concave up at

$(-0.85 , -0.14)$

8 0

3 years ago