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Gala2k [10]
3 years ago
10

Order these from least to greatest 1.5 1.15 1.51 1.1

Mathematics
2 answers:
andrey2020 [161]3 years ago
7 0
1.1,1.5,1.15,1.51 (your welcome)
Paladinen [302]3 years ago
6 0
1.1, 1.5, 1.15, 1.51

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100 / what = 4<br> hellpppp my brain wont work
Ierofanga [76]

Answer:

25

Step-by-step explanation:

Let's call that number x

100/x = 4 now multiply both sides by x to get rid of fraction

100 = 4x divide both sides by 4

25 = x

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4 years ago
Which best describes the relationship between the lines
Dominik [7]

Answer:

B. neither perpendicular nor parallel

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4x^1/2 to radical form
Lyrx [107]
x^ \frac{m}{n}= \sqrt[n]{x^m}
pemdas, so exponent first before multiply
4(x^1/2)=4x^2
this is different from
(4x)^1/2

so

x^ \frac{1}{2}= \sqrt[2]{x^1}
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3 years ago
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A television is originally priced at $1,500. The store owner gives a discount and the television is now priced at
kvv77 [185]

Answer:

975÷1500=0.65

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The answer is 35% discount

6 0
3 years ago
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a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the
kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Step-by-step explanation:

The population growth can be modeled as an exponential function,

P(t) = P_0e^{rt}

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

P(t) = 45e^{0.22t}

Assuming that the starting year is 2020,

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0
3 years ago
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