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4 years ago

12

if i earn 8 dollars after taxes are taken out of my paycheck and my. insurance is 200 a month how many hour would i need to pay

insurance

1 answer:

avanturin [10]4 years ago

8 0

25 hours in all would cover your insurance

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An angle measures 88° more than the measure of a complementary angle. what is the measure of each angle?

aleksandrvk [35]

Let one angle be x
Let second angle be 88+x
Sum of two complementary angles = 90°
x+ 88+ x = 90°
2x + 88 = 90
2x = 90 - 88 = 2
x = 2/2 = 1

First angle = x = 1°
Second angle = 88 + x = 88+1 = 89°
I hope it is helpful:D

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3 years ago

Two airliners are 1600 miles apart and heading toward each other at different altitudes. The first plane is traveling north at 6

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In approximately around 2 hours and 10 mins

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4 years ago

Which expression is equivalent to 5 square root 11^3

AlladinOne [14]

Answer:

11^3/5

Step-by-step explanation:

The exponent of 3 becomes the numerator while the 5 in the root becomes the denominator which creates the fraction 3/5. So the final answer is 11^3/5

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3 years ago

At a bargain store beast boy bought 5 items that each cost the same amount. Cyborg bought 8 items that each cost the same amount

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3 years ago

Given: KLMN is a trapezoid, m∠N=m∠KML, FD=8, LM KN = 3 5 F∈ KL , D∈ MN , ME ⊥ KN KF=FL, MD=DN, ME=3 5 Find: KM

denis23 [38]

Answer:

The length of side KM is $\sqrt{109}$ units.

Step-by-step explanation:

Given information: KLMN is a trapezoid, ∠N= ∠KML, FD=8, LM:KN=3:5, F∈ KL, D∈ MN , ME ⊥ KN KF=FL, MD=DN, $ME=3\sqrt{5}$ .

From the given information it is noticed that the point F and D are midpoints of KL and MN respectively. The height of the trapezoid is $3\sqrt{5}$ .

Midsegment is a line segment which connects the midpoints of not parallel sides. The length of midsegment of average of parallel lines.

Since LM:KN=3:5, therefore LM is 3x and KN is 5x.

$\frac{3x+5x}{2}=8$

$\frac{8x}{2}=8$

$x=2$

Therefore the length of LM is 6 and length of KN is 10.

Draw perpendicular on KN form L and M.

$KN=KA+AE+EN$

$10=6+2(EN)$ (KA=EN, isosceles trapezoid)

$EN=2$

$KE=KN-EN=10-2=8$

Therefore the length of KE is 8.

Use pythagoras theorem is triangle EKM.

$Hypotenuse^2=base^2+perpendicular^2$

$(KM)^2=(KE)^2+(ME)^2$

$(KM)^2=(8)^2+(3\sqrt{5})^2$

$KM^2=64+9(5)$

$KM=\sqrt{109}$

Therefore the length of side KM is $\sqrt{109}$ units.

8 0

4 years ago

Read 2 more answers