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loris [4]
3 years ago
15

Point O is the incenter of ΔABC. What is mQBO? mQBO is ___ degrees.

Mathematics
2 answers:
natta225 [31]3 years ago
5 0
The answer is 12 degrees
Sever21 [200]3 years ago
4 0

Answer:

m\angle QBO=12

Step-by-step explanation:

We have been given that point O is the in-center of triangle ABC. We are asked to find the measure of angle QBO.

We know that in-center of a triangle is the point, where three angle bisectors of triangle meet.

Since O is in-center, so AO will be angle bisector. We will find the value of x by equating the expression for angle QAO to angle SAO as:

2x+6=4x-12

2x+6-6=4x-12-6

2x=4x-18

2x-4x=4x-4x-18

-2x=-18

\frac{-2x}{-2}=\frac{-18}{-2}

x=9

Now we will substitute x=9 in the expression for measure of angle QBO.

m\angle QBO=3x-15

m\angle QBO=3*9-15

m\angle QBO=27-15

m\angle QBO=12

Therefore, the measure of angle QBO is 12 degrees.

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2 years ago
Can someone help me with number 8 please? Thank you.
Naddik [55]
Answer: -4 \le x \le 5
Note: to write the domain in interval notation, you'd write [-4,5]
if you need the domain in set-builder notation, then you'd write \left\{x|x\in\mathbb{R}, \ -4\le x\le 5\right\}

------------------------------------------------------------------------------

Explanation:

The domain is the set of possible x input values. Look at the left most point (-4,-1). The x coordinate here is x = -4. This is the smallest x value allowed. The largest x value allowed is x = 5 for similar reasons, but on the other side of the graph.

So that's how I got -4 \le x \le 5 (x is between -4 and 5; inclusive of both endpoints)

Writing [-4,5] for interval notation tells us that we have an interval from -4 to 5 and we include both endpoints. The square brackets mean "include endpoint"

Writing \left\{x|x\in\mathbb{R}, \ -4\le x\le 5\right\} is the set-builder notation way of expressing the domain. The x\in\mathbb{R} portion means "x is a real number"

6 0
3 years ago
Helppppppp show the steps to your answer
Studentka2010 [4]

The numeric value of the expression -a² - 2bc - |c| for a = -3, b = -5 and c = 2 is of 9.

<h3>How to find the numeric value of an expression?</h3>

The numeric value of an expression is found replacing each letter by it's attributed value.

In this problem, the expression is:

-a² - 2bc - |c|

The attributed values are:

a = -3, b = -5 and c = 2

Hence the numeric value will be given by:

-a² - 2bc - |c| = -(-3)² - 2(-5)(2) - |2| = -(9) + 20 - 2 = -9 + 18 = 9.

More can be learned about the numeric value of an expression at brainly.com/question/14556096

#SPJ1

4 0
10 months ago
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