Is this complementary, linear pair, vertical, or adjacent?

Mathematics

1 answer:

Lorico [155]2 years ago

7 0

I believe it is Complimentary

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Integration by Parts Evaluate e-2x cos(2x) dx.

kifflom [539]

Let

$I = \displaystyle \int e^{-2x} \cos(2x) \, dx[/]texIntegrate by parts:[tex]\displaystyle \int u \, dv = uv - \int v \, du$

with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \cos(2x) \, dx \implies v = \dfrac12 \sin(2x)$

Then

$\displaystyle I = \frac12 e^{-2x} \sin(2x) + \int e^{-2x} \sin(2x) \, dx + C$

Integrate by parts again, this time with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \sin(2x) \, dx \implies v = -\dfrac12 \cos(2x)$

so that

$\displaystyle I = \frac12 e^{-2x} \sin(2x) - \frac12 e^{-2x} \cos(2x) - \int e^{-2x} \cos(2x) \, dx + C\\\\ \implies I = \frac{\sin(2x)-\cos(2x)}{2e^{2x}} - I + C \\\\ \implies 2I = \frac{\sin(2x) - \cos(2x)}{2e^{2x}} + C \\\\ \implies I = \boxed{\frac{\sin(2x) - \cos(2x)}{4e^{2x}} + C}$

6 0

1 year ago

Divide 2.875x10^6by2.3x10^3

DerKrebs [107]

Answer:

1875L = 1.875x10^6 mL

multiply by density to get 2.14x10^6

multiply by percentage to get 6.63x10^4 g of NaCl (66.3 kg)

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The diameter of fishing line varies. Fishing lines can have a diameter as small as 2 x 102 inch and as large as 6 x 10-2 inch. H

Reil [10]

Answer:
3 times

Explanation:
We know that:
small diameter = 2 * 10^-2 in
large diameter = 6 * 10^-2 in

We want to know how many times larger is the thin diameter compared to the large one.
We will do this as follows:
large diameter = k * small diameter
where k is the number of times that we want to find
6 * 10^-2 = k * 2 * 10^-2
k = (6 * 10^-2) / (2 * 10^-2)
k = 3

This means that the large diameter is 3 times the small one.

Hope this helps :)

4 0

3 years ago

PLEASE HELP ME ASAP..................................

kow [346]

Answer:

2, 4, 5

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Pleaseeee help I’ll mark you as Brainly if the answers correct with no link just tell me please

Ksenya-84 [330]